In 1966-1968 Yuri Manin gave a 2 year lecture course in algebraic geometry at Moscow State University. The course starts from scratch and culminates in the proof of the Riemann-Roch theorem following SGA6 with some simplifications. The course was subsequently published by the Moscow University Press in two parts. Part 2 contained the proof of the Riemann-Roch theorem and Part 1 the preliminary material. (Part 2 also appeared as a paper in the Russian Mathematical Surveys.)

However, the version of Part 1 that I have has only chapters 1 to 15, and in Part 2 Manin makes references to chapters 25 and 22 of Part 1. This is why I would like to ask whether any more of Part 1 exists, apart from chapters 1-15, and if so, whether it has been made publicly available.

Thank you.

  • $\begingroup$ Do you read Russian? $\endgroup$ Feb 25, 2012 at 23:05
  • 4
    $\begingroup$ Yes, I can read Russian. $\endgroup$
    – the_dude
    Feb 25, 2012 at 23:17
  • 1
    $\begingroup$ Have you seen this question and answers to it? mathoverflow.net/questions/72068/… $\endgroup$ Feb 26, 2012 at 4:38
  • 1
    $\begingroup$ @Mahdi: That is the notes OP mentions. The first part goes up to Section 15. $\endgroup$
    – user6976
    Feb 26, 2012 at 8:23

1 Answer 1



I've uploaded the scan of complete 1966-1968 lectures. The site doesn't seem to work pretty well, so in case you're unable to download it I can send it by email.

  • $\begingroup$ Hi Dmitry, I am interested in the note but I cannot find your email address. I would rather make this as a comment, but my reputation point is still below 50. If you read this posting, please send your note to [email protected]. I would appreciate it. $\endgroup$ Jun 23, 2012 at 22:43
  • 5
    $\begingroup$ You could upload it on Google Drive and make it public. $\endgroup$ Jun 24, 2012 at 5:08
  • 1
    $\begingroup$ The link doesn't work. Could you send those notes to me? $\endgroup$ May 3, 2013 at 23:29
  • $\begingroup$ (Click on my name to find my email address) $\endgroup$ May 3, 2013 at 23:30
  • 3
    $\begingroup$ The link in this answer is broken. Perhaps someone who got a copy could act on Chandan's suggestion? $\endgroup$
    – David Roberts
    Apr 10, 2014 at 4:24

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.