Let $(M,g)$ be a closed, compact Riemannian manifold. Let $P$ be a $2r$th order pseudo-differential operator, where $r \in \Bbb{R}_+$. Suppose that the differential equation $Pu=f$ has a unique $H^r(M)$ solution for all $f$ in the dual space of $H^r(M)$. Does it follow that $P$ is elliptic?
1 Answer
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Yes, this is correct. You can find a more general result in
Topics in pseudo-differential operators. 1969 Pseudo-Diff. Operators (C.I.M.E., Stresa, 1968) pp. 167–305 Edizioni Cremonese, Rome
More precisely see Corollary 1, Chap. IV, page 251 in the above reference.
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$\begingroup$ Great! Thanks for the reference. It's exactly what I needed. $\endgroup$ Commented Feb 20, 2012 at 6:40