-2
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the 2 in the denominator, I used the quotient rule and then multiplied the fraction by x to the 1/2, which allowed me to do some factorizing to cancel out the denominator. However, I am left with simply a square root 2 at the bottom, and I'm not quite sure where that 2 comes from. I'm starting to suspect the question might be wrong in itself.

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2
  • $\begingroup$ This site is for research level questions. For general questions in mathematics see math.stackexchange.com, but study this guide first before asking any question there: math.meta.stackexchange.com/q/9959 $\endgroup$
    – GH from MO
    Commented 4 hours ago
  • $\begingroup$ BTW the fraction equals $\sqrt{x}-2$, whose derivative is the right-hand side. So there is no mistake in the displayed formula. $\endgroup$
    – GH from MO
    Commented 4 hours ago

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