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I want to construct an $n$-simplex the following way:

  • Choose $n$ vectors in the boundary of an $n$ dimensional ball, which are forming an $(n-1)$-simplex together.

  • Place the orthogonal affine $n-1$-hyperplane on each of these vectors.

My question now is: Does the part enclosed by these hyperplanes together with the $(n-1)$-simplex now form an $n$-simplex?

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  • $\begingroup$ By "$n$-simplex" do you mean a regular $n$-simplex? $\endgroup$ Commented Aug 21 at 0:33
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    $\begingroup$ Yes. It comes out to the question whether those hyperplanes (given the circumstances) all intersect in one point, which becomes the $n+1$ vertex of the $n$-Simplex. $\endgroup$ Commented Aug 21 at 5:15

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