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$\DeclareMathOperator\GK{GK}$Let $k$ be the base field.

The Gelfand-Kirillov dimension was introduced by Gelfand and Kirillov in their seminal paper on the Gelfand-Kirillov conjecture.

A very famous paper that brought a lot of attention to the subject is Borho and Kraft 'Über die Gelfand-Kirillov Dimension', and for some time the paper was used a lot, until it was superseded by new presentations of the subject – such as Krause and Lenegan book on GK-dimension.

Eventually, people discovered that some results in Borho and Kraft's paper were false. One of their statement was: let $A$ and $B$ be two affine algebras, and consider their tensor product as an algebra. Then $$\GK( A \otimes_k B) = \GK ( A )+ \GK (B).$$

Albeit being an extremely natural thing to expect, this result is false, as was discovered by Warfield. He also provided a very simple technical assumption that makes that result true:

(Warfield) Consider a finite dimensional vector space $V$ which contains $1$ and generates $A$ as an algebra. Let $d_V(n)=\dim_k V^n$ where inductively, $V^0=k, V^n=V. V^{n-1}$ Suppose $\GK(A)=\lim_{n \to \infty} \log_n d_V(n)$. Then $$\GK( A \otimes_k B) = \GK ( A )+ \GK (B).$$

The above condition holds for almost commutative algebras, Noetherian PI-algebras, etc.

Now to my question proper.

Let $A$ and $B$ be two affine algebras, $M$ a f.g. left $A$-module, $N$ a f.g. left $B$-module. We can turn $M \otimes_k N$ into an $D:= A \otimes_k B$-module.

Is $\GK_D(M \otimes N)=\GK_A(M)+\GK_B(N)$? I know this is true, for instance, for holonomic modules for the Weyl algebras. But what can be said in general?

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  • $\begingroup$ Sorry, what precisely is $V^n$ here? Please define it. $\endgroup$
    – AlexIvanov
    Commented May 29 at 7:07
  • $\begingroup$ @AlexIvanov: If $V$ is linearly generated by the algebra generators $a_1,\dots,a_m$, then $V^n$ is the linear space generated by all monomials in $a_1,\dots, a_m$ of length $n$. (It is somewhat standard notation in GK-dim. theory.) $\endgroup$
    – M.G.
    Commented May 29 at 8:40

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