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$\DeclareMathOperator\GL{GL}$Let $G$ be a linear algebraic group (probably reductive will be needed). Consider a faithful representation $G \to \GL(V)$. Given a parabolic subgroup $P < G$, we can consider a composition series of $V$ as a $P$-module

$$ V_\bullet: 0 \subseteq V_1 \subseteq V_2 \subseteq \dotsb \subseteq V_s = V, $$ i.e. each $V_i$ is $P$-invariant and the flag is maximal in the sense that the quotients $V_i/V_{i-1}$ are irreducible representations for $P$.

I would really appreciate it if you could help me to shed some light on the following questions:

  • (Main question) Is it true that $P$ is the stabilizer of this composition series, i.e. is $$ \operatorname{Stab}_G(V_\bullet) = \{g \in G \mid gV_i \subseteq V_i \text{ for all }i\} $$ exactly equal to $P$ (or conjugated to it)?
  • In the case the answer is "yes": is it true that the Levi subgroup associated to $P$ is exactly the collection of $g \in G$ preserving the graded object attached to $V_\bullet$?
  • In the case the answer is "no" for a general representation $V$: Is there a particular representation for which the previous sentences hold true?

Some comments

  • If I'm not mistaken, the result is true for $G = \GL_n$ with the obvious representation. Indeed, the parabolic subgroups are “fat upper triangular” subgroups, and the steps in the staircase determine the flag. Actually, for “classic groups” such as $\GL_n$, $\operatorname{SL}_n$ or $\operatorname O_n$, I think the result holds true using an appropriate “isotropic flag”. My question is about a general reductive group.
  • If $P=B$ is the Borel subgroup, the result (at least, the first question) is true. Indeed, it is typically the way you prove that $G/B$ is projective, by showing it is isomorphic to the variety of full flags. But the proof I know uses Lie–Kolchin's theorem, which requires the subgroup to be solvable.
  • I'm aware that $G/P$ is usually referred to as the "partial flag variety" (which partially motivates by question), but I never saw that this variety can be actually understood as a genuine variety of (partial) flags. In particular, a related question would be: Is it possible to identify $G/P$ for a parabolic subgroup $P$ as a certain subvariety of the full flag variety $G/B$?
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$\DeclareMathOperator\GL{GL}$Yes for reductive $G$, and this follows quickly from the dynamical characterization of parabolics: A subgroup $H$ of a reductive group $G$ is parabolic if and only if there is some $\mu \colon \mathbb G_m \to G$ such that $$H = \{ g \in G \mid \lim_{t\to 0} \mu(t) g \mu(t)^{-1} \text{ exists}\}.$$

A faithful representation $V$ of $G$ of dimension $n$ defines an embedding of $G$ into $\GL_n$ and this definition makes clear that every parabolic is the inverse image of a parabolic from $\GL_n$. The parabolic in $\GL_n$ is expressed as the stabilizer of a filtration, so $P$ is the stabilizer in $G$ of that filtration. Since $P$ stabilizes that filtration, that filtration is a coarsening of the composition series of $V$ as a $P$-module, so $P$ is also the stabilizer of the composition series.

One can directly see that this subgroup is the stabilizer of a filtration, without using the classification of parabolics of $\GL_n$ (or rather by reproving it) by choosing a basis of $V$ by eigenspaces of $\mu(t)$, noting that the limit exists if and only if the entries of $g$ corresponding to a pair of basis vectors where the first one has a larger eigenvalue all vanish, i.e. if $g$ preserves a filtration into sums of eigenspaces with eigenvalue less than or equal to a given one.

For the follow-up question, I don't think "the graded object attached to $V$" is well-defined. There are many possible ways of splitting a filtration, and some might have tiny stabilizers. However, any Levi certainly gives a splitting (via the decomposition of $V$ as a direct sum of irreducible representations of the Levi) and the Levi is the stabilizer of that splitting because of the characterization of the Levi as the centralizer of the image of a homomorphism $\mu \colon \mathbb G_m \to G$, hence the stabilizer of the splitting of $V$ into eigenspaces of $\mu$, and hence the stabilizer of its own decomposition into irreducible representations, which coarsens that one.

Why would you expect a partial flag variety to be a subvariety of the full flag variety. I don't think it usually is. "Partial" means information is forgotten, i.e. the partial flag variety admits a surjective map from the full flag variety. It doesn't refer to being a part of a full flag variety.

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    $\begingroup$ $V = \operatorname{Add}^n$, I guess. I'm not quite sure what you mean in the algebraic setting by referring to larger and smaller eigenvalues. Also, there's no harm in assuming reductivity because it has been tentatively assumed in the original post, but you might want to mention that identifying parabolic subgroups as you do is where you use reductivity. $\endgroup$
    – LSpice
    Commented Mar 24 at 1:40
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    $\begingroup$ @LSpice Good point about the reductive assumption. The eigenvalue of a representation of $\mathbb G_m$ is a character of $\mathbb G_m$, which can be expressed as an integer, viewing the $d$th power representation as $d$. I mean larger or smaller integers. I can't get the sign convention right so there's a $50\%$ chance I want to take the $d$th power representation as $-d$ or something like that. I think my eddit addresses your first sentence but I'm not sure. $\endgroup$
    – Will Sawin
    Commented Mar 24 at 1:50
  • $\begingroup$ Re, yes, your edit addresses my first point. And, because I didn't read carefully, I thought you were somehow placing an order on the eigenvalues of an arbitrary element of $\operatorname{GL}_n$, not of $\operatorname{GL}_1$; I agree now that the latter is what you said, and that it makes sense. $\endgroup$
    – LSpice
    Commented Mar 24 at 1:53
  • $\begingroup$ $\DeclareMathOperator\GL{GL}$@WillSawin, thanks a lot for the great answer! Stupid question: How do you know that there are "enough eigenvalues" in cocharacters of $G$? More precisely, to prove that any $P < G$ is the restriction of a parabolic of $\GL_n$, you need to show that if the limit exists for every $\mu(t) < G$, then it also exists for every $\mu'(t) < \GL_n$. But, in principle, the configuration of different eigenvalues allowed in $\mu(t)$ might be less than the ones allowed in $\mu'(t)$. Obviously, I cannot find a counterexample cause I'm sure the claim is true, but I cannot see it. $\endgroup$
    – a_g
    Commented Mar 24 at 11:10
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    $\begingroup$ @a_g There is no "for all $\mu$" quantifier in the definition so this is irrelevant. $\endgroup$
    – Will Sawin
    Commented Mar 24 at 13:27

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