Following [Neumann P.M., The lawlessness of groups of finitary permutation groups, Arch. Math. 55(6) 1990, 521-532], we define totally imprimitive groups in a more general form as follows:
Let $G$ be a transitive subgroup of Sym$(\Omega)$ for some countably infinite set $\Omega$. If there is a chain of proper $G$-blocks $$\Delta_0\subset \Delta_1\dots\subset \Delta_i\subset\dots$$ such that $\bigcup_{i\in\omega}\Delta_i=\Omega$, i.e. there is no maximal $G$-block, then $G$ is called totally imprimitive. My question is:
Is there a totally imprimitive subgroup $G$ such that Alt$(\Omega)<G< $Sym$(\Omega)$, where Alt$(\Omega)$ is the alternating subgroup of Sym$(\Omega)$?