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Over a field $ k $ of characteristic zero, actions of $ \widehat{\mathbb{G}_{a}} $ on a variety $ \operatorname{Spec}(A) $ are obtained from $ A $-derivations $ \delta $ of $ A $ over $ k $ via the co-action below: \begin{equation*} a \mapsto \sum_{j=0}^{\infty} \frac{\delta^{j}(a)t^{j}}{j!}. \end{equation*} The sheaf $ \Omega_{A/k} $ parameterizes $ A $-derivations of $ A $ over $ k $.

If $ k $ is a field of positive characteristic then actions of $ \widehat{\mathbb{G}_{a}} $ are parameterized by iterative, higher derivations. A collection of $ k $-homomorphisms $ \phi_{i}: A \to A $ is a higher derivation if $ \phi_{0} = \operatorname{id}_{A} $ and $ \phi_{n}(a_{1}a_{2}) = \sum_{(i,j) \in \mathbb{N}_{0}^{2}} \phi_{i}(a_{1}) \phi_{j}(a_{2}) $. A higher derivation is called iterative if $ \phi_{i} \circ \phi_{j} = \binom{i+j}{i} \phi_{i+j} $. One obtains an action of $ \widehat{\mathbb{G}_{a}} $ on $ \operatorname{Spec}(A) $ from an iterative, higher derivation $ \{\phi_{i}\}_{i \in \mathbb{N}_{0}} $ via the co-action below: \begin{equation*} a \mapsto \sum_{j=0}^{\infty} \phi_{j}(a)t^{j}. \end{equation*}

One could generalize the notion of a $ B $-derivation of $ M $ over $ A $ as follows. Let $ J_{B/A} $ be the kernel of the ring homomorphism $ B \otimes_{A} B \to B $ which sends $ b_{1} \otimes b_{2} $ to $ b_{1}b_{2} $. Define $ \delta_{i}(b) $ to be the image of $ b \otimes_{A} 1 $ in $ J_{B/A}^{i}/J_{B/A}^{i+1} $ so that the image of $ b $ in $ \prod_{i \in \mathbb{N}_{0}} J_{B/A}^{i}/J_{B/A}^{i+1} $ is $ \{\delta_{i}(b)\}_{i \in \mathbb{N}_{0}} $. A higher $ B $-derivation of $ M $ over $ A $ is a homomorphism $ \phi: B \to \prod_{i \in \mathbb{N}_{0}} J_{B/A}^{i}(B \otimes_{A} M)/J_{B/A}^{i+1}(B \otimes_{A} M) $ such that if $ \phi_{i}(b) \in J_{B/A}^{i}(B \otimes_{A} M)/J_{B/A}^{i+1} $ and $ \phi(b) = \{\phi_{i}(b)\}_{i \in \mathbb{N}_{0}} $, then $ \phi_{n}(b_{1}b_{2}) = \sum_{(i,j) \in \mathbb{N}_{0}^{2}, i+j=n} \delta_{i}(b_{1})\phi_{j}(b_{2}) $. However, there might be a more optimal way to generalize the notion of a $ B $-derivation of $ M $ over $ k $ to higher derivations so that one could define a sheaf $ \Xi_{A/k} $ with a similar universal property to $ \Omega_{A/k} $.

Has anyone tried to generalize the notion of higher differentials so that one could create a sheaf $ \Xi_{A/k} $ with a similar universal property to that of $ \Omega_{A/k} $ for derivations? Specifically are there any references in the literature of such a generalization and sheaf $ \Xi_{A/k} $?

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    $\begingroup$ Related: mathoverflow.net/questions/434693 $\endgroup$ Commented Nov 25, 2022 at 19:45
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    $\begingroup$ I am not sure if the question is well-defined. For the definition of $\Omega^1_{A/k}$ we need the notion of a derivation $A \to M$ where $M$ is any $A$-module. In the description using $\mathbb{G}_a$-actions only derivations $A \to A$ appear. In your proposed definition of $\Xi_{A/k}$ we also only talk about maps $A \to A$ and even compose them. How are we supposed to generalize this to maps $A \to M$? $\endgroup$ Commented Nov 25, 2022 at 19:47
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    $\begingroup$ We would need to generalize the notion of a higher differential to define higher derivations of $ A$ into $M $ over $ k $. That is meant to be included in the question. $\endgroup$
    – Schemer1
    Commented Nov 25, 2022 at 19:50
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    $\begingroup$ I believe there is a way to make such a generalization, and I want to know if it is already in the literature. $\endgroup$
    – Schemer1
    Commented Nov 25, 2022 at 19:51
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    $\begingroup$ I see. Then it would be very helpful if you add this generalization to the post. Also, when you are just looking for literature, the tag "reference request" is useful. $\endgroup$ Commented Nov 25, 2022 at 19:52

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I have this strange feeling I have commented on this or an identical question recently, but can't place it.

Here is one solution which may not be what you are looking for and you have mentioned it in your question.

Let $A$ be a $B$- algebra (all commutative) and let $M$ be an $A$-module. A $B$- module homomorphism $D:A\to M$ is a differential operator of order $\leq n$, if $[D,a]$, the Lie bracket, is a differential operator of order $\leq n-1$ for all $a\in A$. Of course differential operator of order zero is just an $A$-module homomorphism.

Then the universal object is got as follows. Let $J$ (as in question) be the kernel of the multiplication map $A\otimes_B A\to A$. For any $n$, one has the $A$- module $D_n=A\otimes_B A/J^{n+1}$ where the module structure is from the left factor, say. Then one has a $B$-module map $d:A\to D_n$ given by $d(a)=1\otimes a$ and one can check that this is a differential operator of order $n$ and has the required universal property.

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