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Given $U : \mathbb{R^2} \to \mathbb{R}$ is monotone and quasi-concave, consider the following problem :

$$\max_{(x,y) \ \in \ \mathbb{R}^2}[U(x,y)] \text{ subject to } p_1 x + p_2 y \leq M ; \ (p_1, p_2 > 0)$$

1. If a level curve of $U$ is tangent to $p_1 x + p_2 y = M$ at some point $(a,b)$ on such that the slope of the tangent is $-\frac{p_1}{p_2}$, then show that it is an optimal point.

I have seen the tangency condition to be written as $\displaystyle \frac{df(x)}{dx} = -\frac{\frac{\partial U(x,y)}{\partial x}}{\frac{\partial U(x,y)}{\partial y}} = -\frac{p_1}{p_2}$ where $f: (a-\epsilon, a+\epsilon) \to \mathbb{R}$ describes the level curve around the point $(a,b)$.

2. Is it possible to have $\frac{df(x)}{dx} = -\frac{p_1}{p_2}$ but one or both of $\frac{\partial U(x,y)}{\partial x}$ and $\frac{\partial U(x,y)}{\partial y}$ are not defined?


My attempt:

If $U$ is differentiable at all points, then the Karush-Kuhn-Tucker condition is satisfied and (1) follows. For (2), each term is defined due to our assumption.

The problem lies when $U$ is not differentiable everywhere. In that case, how do we show that the point of tangency is an optimal point? I don't know if the tangency condition requires all the derivatives in (2) to be defined in the interval around $(a,b)$; assume differentiability of $U$ in that particular region around $(a,b)$ only if that is a necessity.


Definitions:

  1. Quasi-concavity of $U$ :

    • (Definition $1$) If $U(r) \geq U(s)$ for $r,s \in \mathbb{R}^2$, then $U(\lambda r + (1-\lambda)s) \geq U(s) \ \forall \lambda \in [0,1]$.

    • (Definition $2$) The set $S_\alpha := \{ (x,y) : U(x,y) \geq \alpha\}$ is convex for all values of $\alpha$.

  2. Monotonicity of $U$ :

    • $r \geq s \implies U(r) \geq U(s)$ where $r \geq s$ means $(r_1 \geq r_2) \land (s_1 \geq s_2)$ for $r = (r_1, r_2)$ and $s = (s_1, s_2)$.
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For your question 2: there can be a function with discontinuities, which still has smooth level curves.

E.g. $U(x, y) = x + y + \lfloor x+y \rfloor$. It is monotone, quasi-concave, and level curves are straight lines; but the function is discontinuous at lines where $x + y$ is an integer.

For question 1: instead of "tangent", it seems the following lighter condition may work: if a level curve of $U$ has an intersection with $p_1 x + p_2 y = M$, and the level curve is entirely on one side of $p_1 x + p_2 y = M$. That would free us from differentiability. But I have no proof of it.

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  • $\begingroup$ Two quick follow-ups: (i) The level curve of $x+y+\lfloor x+y \rfloor = 2k$ where $k \in \mathbb{Z}$ is $x+y=k$. Is that correct? I mean to say that the individual level curves do not have a point of discontinuity. (ii) Again, just to clarify, this example does not contradict our original problem, right? No level curve forms a tangent unless $p_1 = p_2$. When $p_1 = p_2$, we have $\frac{df(x)}{dx} = -1 = -\frac{p_1}{p_2}$ and every point on it intersecting with $p_1 x+ p_2 y = M$ will be optimal. (The partials don't have not exist, so this works!) Is my understanding correct? $\endgroup$ Commented Jun 25, 2022 at 0:02
  • $\begingroup$ I would have given you a +1 for the example, but it seems I need at 15 reputation points to do so. $\endgroup$ Commented Jun 25, 2022 at 0:11
  • $\begingroup$ That's right, the example does not contradict the original problem. It is there to answer positively to question 2, i.e. it shows that the level curve can be defined and have a tangent, while $U$ is not continuous (and so lacks some partial derivative). $\endgroup$ Commented Jun 25, 2022 at 0:56

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