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Compare the following two results:

Thm A) Let $A$ be a commutative $C^*$-algebra and let $X$ be its Gelfand spectrum. Gelfand duality says that there's a natural isometric $*$-isomorphism from $A$ to $C(X)$, the $C^*$-algebra of continuous functions on $X$.

Thm B) Let $A$ be a commutative ring and $X=\operatorname{Spec}A$. There's a natural sheaf of rings $\mathscr{O}$ on $X$ such that $A=\Gamma(X,\mathscr{O})$.

Both theorems are very close. I wonder if it's possible to obtain theorem A as a particular case of theorem B, or a variant thereof.

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    $\begingroup$ Affine varieties are not locally compact and Hausdorff, nor all rings are commutative C-star algebras, so no, but both results have the same flavour. $\endgroup$ Commented Jan 13, 2022 at 10:11
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    $\begingroup$ This answer seems to suggest otherwise? mathoverflow.net/a/90810/131975 $\endgroup$
    – Gabriel
    Commented Jan 13, 2022 at 10:29
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    $\begingroup$ The spectrum of a commutative C*-algebra is the space of maximal ideals (max spec). This is only the prime spectrum when the space X os totally disconnected. $\endgroup$ Commented Jan 13, 2022 at 10:55
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    $\begingroup$ All Zarsiki open subsets of the sepctrum of a C-star algebra are open (complememt of vanishing locus of a continuous function is open). So the Zarsiki topology is coarser. If the spectrum of a unital algebra is compact and Hausdorff, then it is normal. (T4). In that case it seems that you could use the extension theorem to prove the that the Zarsiki topology is also finer. Namely, for any point and neighborhood of it, there is a continuous function that does not banish on the point, but vanishes on the complement of the neighborhood. $\endgroup$
    – afh
    Commented Jan 13, 2022 at 13:13
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    $\begingroup$ If you are searching a common categorical generalization, you might start here: andrew.cmu.edu/user/awodey/preprints/lambek.pdf $\endgroup$
    – NameNo
    Commented Jan 13, 2022 at 13:31

2 Answers 2

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Yes, both Theorem A and Theorem B are special cases of a more general construction.

Denote by $R$ the category of commutative unital C*-algebras or the category of commutative rings. Denote by $R'$ the full subcategory of $R$ given by reduced objects in $R$, meaning the only nilpotent element is zero. (All commutative unital C*-algebras are reduced.)

Given an object $X∈R$, we can consider its poset $\def\Spec{\mathop{\sf Spec}}\Spec X$ of quotient objects (= subobjects in the opposite category) that belong to $R'$.

One can show that $\Spec X$ is a locale, the (localic) Zariski/Gelfand spectrum of $X$. Furthermore, assuming the axiom of choice, this locale is spatial, so it corresponds to a topological space, namely, the traditional Zariski/Gelfand spectrum of $X$.

Given an open element $U$ of $\Spec X$ corresponding to a reduced quotient $X→Q$, its kernel $I⊂X$ is a radical ideal and we can consider the localization $X[S^{-1}]∈R$, defined using a universal property in the category $R$, where $S=\{a∈X\mid I⊂\sqrt{(a)}\}$.

The assignment $$U↦X[S^{-1}]$$ defines a sheaf on $\Spec X$ valued in $R$. This is precisely the structure sheaf of $\Spec X$ for both the Gelfand spectrum and the Zariski spectrum.

Of course, this construction is applicable to many other categories $R$:

  • finitely presented entire functional calculus algebras, recovering the Stein duality for globally finitely presented Stein spaces (i.e., complex geometry).
  • finitely generated germ-determined C^∞-rings, recovering the Dubuc duality for C^∞-loci (i.e., differential geometry);
  • other dualities for algebraic geometry, such as formal schemes, etc.
  • various versions of the above for derived geometry;
  • Boolean algebras, recovering the Stone duality for compact totally disconnected Hausdorff spaces;
  • complete Boolean algebras, recovering the Stonean duality for compact extremally disconnected Hausdorff spaces;
  • localizable Boolean algebras, recovering the Gelfand-type duality for compact strictly localizable enhanced measurable spaces.
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    $\begingroup$ Do you happen to have "general conditions" on a(n abstract + maybe some structure ) category $R$ for such a construction to work and give similar results ? $\endgroup$ Commented Jan 14, 2022 at 8:45
  • $\begingroup$ Note that for Gelfand one uses only maximal i.e. prime and closed ideals (not all prime ideals). Se my first two comments to the question. The "commutative reduced = subdirect product of commutative domains", here glorified by a topology, is one of many kinds of (different) decompositions that become quite interesting for noncommutative (or Jordan) rings but all coincide for Boolean algebras. $\endgroup$
    – NameNo
    Commented Jan 14, 2022 at 12:51
  • $\begingroup$ The special relation between prime and maximal ideals in Gelfand's case (every prime extends uniquely to a maximal; see 4.5 in this or the classical) explains why and how A) can be reduced to B) i.e. why the maximal spectrum (as subspace of the prime spectrum) is enough: core.ac.uk/download/pdf/82558373.pdf $\endgroup$
    – NameNo
    Commented Jan 14, 2022 at 16:59
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    $\begingroup$ @MaximeRamzi: As far as I am aware, nobody has figured this out yet. I think Iskra's Really Modern Algebra describes how to recover R' from R in categorical terms (and makes many other interesting observations), and a recent question by John Baez makes some initial steps toward characterizing R, but there is a lot more to do. $\endgroup$ Commented Jan 14, 2022 at 19:02
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    $\begingroup$ References for most items can be found by following the hyperlinks in ncatlab.org/nlab/show/duality+between+algebra+and+geometry. For the last three items, see also arxiv.org/abs/2005.05284. I am not aware of a single unifying source. $\endgroup$ Commented Dec 15, 2023 at 1:19
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As @PaulTaylor said, the book Stone Spaces by Peter Johnstone has some stuff about this. I'll explain below, in my words, the parts that I found relevant.

Let $A$ be a commutative (unital) $C^*$-algebra. Its Gelfand spectrum $\operatorname{sp}(A)$ is usually defined as the set of nontrivial multiplicative linear functionals with the weak-$*$ topology. It's a well-known result that the map $\operatorname{sp}(A)\to\operatorname{Specm}(A)$, sending $\varphi$ to $\ker\varphi$ is a bijection.

In the case of $C^*$-algebras over $\mathbb{R}$, this book affirms that this map is actually a homeomorphism. (The cited function $\hat{a}$ is the one that sends a maximal ideal $\mathfrak{m}$ to the image of $a$ through $A\to A/\mathfrak{m}\cong\mathbb{R}$.)

(I tried to prove that the same holds for complex $C^*$-algebras without much success.)

Answering @YemonChoi comments: the cited book proves (theorem IV.4.10) that the functor $\operatorname{Specm}$ defines a duality between the category of compact Hausdorff spaces and the full subcategory of $\mathsf{CRing}$ whose objects are real $C^*$-algebras. Moreover, he proves an analogous result to the Gelfand duality in section V.3.8 using only the prime spectrum. But I have to say that I found it somewhat unsatisfying.

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  • $\begingroup$ Yes with purely real commutative C$^*$-algebras (involution is identity). But consider yourself what happens for general commutative real C$^*$-algebras (equivalently complex commutative C$^*$-algebras with a fixed involution), for example taking two copies of the same compact T$_2$ space and the involution, on the algebra of continuous functions, that corresponds to the exchange of the two components. $\endgroup$
    – NameNo
    Commented Jan 14, 2022 at 10:09
  • $\begingroup$ @NameNo thank you for your remark, I hadn't realized that. $\endgroup$
    – Gabriel
    Commented Jan 14, 2022 at 10:17

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