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Suppose $(X,\mu)$ is a probability space, and $T_n, n \in \mathbb N$, is a sequence of periodic measure preserving transformations. For $x \in X$ and $f : X \to \mathbb R$, let $\mathrm{avg}_{f,n}(x)$ be the average value of the finite set $\{ f(T_n^0(x)), f(T_n^1(x)), f(T_n^2(x)),\dots\}$ (finite because of periodicity).

I want to know, is there a general “ergodic” theorem that tells us under certain conditions on the sequence $T_n$, $\lim_{n \to \infty} \mathrm{avg}_{f,n}(x) =\int f d\mu$ for $\mu$-almost all $x$, when $f$ is integrable?

Note that typically none of the $T_n$ are ergodic, and they might have a non-ergodic limit. For example, $T_n$ could be translation by $1/n$ on the unit interval. But I think the equation holds in this case.

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  • $\begingroup$ Can the period for $T$ depend on $x$? $\endgroup$
    – Nate River
    Commented May 16, 2021 at 21:20

1 Answer 1

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In fact, for the example you give, there is a failure of pointwise convergence. That was established in a short 1964 paper of Rudin in Proc. Amer. Math. Soc. A more detailed look at this example appears in "The strong sweeping out property for lacunary sequences, Riemann sums, convolution powers, and related matters" by Akcoglu, Bellow, Jones, Losert, Reinhold-Larsson and Wierdl (ETDS 1996).

The general conditions to have this kind of limit are:

  1. a weak $L^1$ maximal theorem;
  2. existence of a dense set of functions $f$ for which convergence occurs.

In your example, you have condition 2. but not condition 1. For more information, have a look at my answer to this question, as well as some of the references that appear as comments in that question.

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  • $\begingroup$ I should add that Rudin cites a very simple counterexample (that was probably known before Rudin's paper): the function $f(x)=x^{-(1/2+\epsilon)}$ is a counterexample for any $0<\epsilon<\frac 12$. For these functions, $\limsup\text{avg}_{f,n}(x)=\infty$ a.e. $\endgroup$ Commented May 20, 2021 at 18:05

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