Sorry if this question is maybe a bit basic, but it is on a rather specialized topic so I think it is more appropriate for MO than SE.
Suppose that $X$ is a simplicial set that has finitely many non-degenerate simplices in every simplicial dimension. Then of course $X$ has finite $\mathbb{Q}$-type (i.e. $H_n(X;\mathbb{Q})$ is finite dimensional as $\mathbb{Q}$-vector space for all $n\ge1$).
Let $Y$ be a fibrant resolution of $X$, that is, $Y$ is a Kan complex and we have a weak equivalence $X\stackrel{\sim}{\to}Y$. I would like to say that $Y$ also has finite $\mathbb{Q}$-type. Is this true?
This is where I get stuck: we know that being of finite $\mathbb{Q}$-type is equivalent to $\pi_n(Y;\mathbb{Q})$ is finite dimensional for all $n\ge2$ and $H_1(Y;\mathbb{Q})$ is finite dimensional. The first part of the condition holds because it holds for $X$ and $Y$ is weakly equivalent to $X$. However, I am unsure how to show that $H_1(Y;\mathbb{Q})$ is finite dimensional.
Any help and/or references would be greatly appreciated! I am also iterested in the case where we only assume $X$ to be of finite type (which should work with the same proof, hopefully).