$\newcommand{\cat}{\mathsf} \newcommand{\fun}{\mathrm{Fun}} \newcommand{\calg}{\mathrm{CAlg}}$ Let $\cat C^\otimes,\cat D^\otimes, \cat E^\otimes$ be symmetric monoidal $\infty$-categories, and $p^\otimes: \cat D^\otimes \to \cat E^\otimes$ a map of $\infty$-operads (aka a lax symmetric monoidal functor).
Assume $p: \cat D\to \cat E$ is a cartesian fibration.
I'd like to know under what natural conditions $\fun^{lax}(\cat C^\otimes,\cat D^\otimes)\to \fun^{lax}(\cat C^\otimes,\cat E^\otimes)$ is still a cartesian fibration, and more specifically if there are references regarding this type of situation.
A few remarks:
- In the cases I'm interested in, $p^\otimes$ is a map of symmetric monoidal $\infty$-categories, so a strict symmetric monoidal functor. If that's necessary to give an interesting statement, I'm willing to assume it.
- Still in those cases, $\cat{D,E}$ are presentable with a compatible tensor product, and I can reduce to the case where $\cat C$ is small, so using Day-convolution, one can reduce to the question of whether $\calg(\cat D)\to \calg(\cat E)$ is still a cartesian fibration, i.e. to the case $\cat C = N(Fin_*)$.
- Finally, I'm also in a situation where $p$ is a "monoidal fibration", by which I mean that if $x\to y$ is a $p$-cartesian edge, then so is $x\otimes z\to y\otimes z$; I think this can be relevant - and hopefully this, together with the first bullet point, should be enough.
Has something like this been written up anywhere ?
EDIT : I wrote down what I think is a complete proof, and indeed items 1 and 3 are the ones that make it work. But the proof is long for this sort of technical result and I'm still interested in references so as not to lengthen what I'm writing too much.