Given a compact, smooth manifold $M$ and a real vector bundle $E \to M$ (in general not flat). There already have been numerous questions about how to equip the space $\bigoplus_k \Gamma(\Lambda^k T^* M \otimes E) = : \Gamma(\Lambda^\bullet T^* M \otimes E)$ with a nontrivial generalization of the de Rham differential making the space into a complex. This, in general, only seems nicely possible if $E$ admits a flat connection, see for example here and here.
Now, I have a situation in which I know what I want my cohomology to be, but I do not know a good candidate for what my differential could be. To be precise, if $V$ is the standard fiber of $E$, I would like to equip the space $\Gamma(\Lambda^\bullet T^* M \otimes E)$ with a differential $d : \Gamma(\Lambda^\bullet T^* M \otimes E) \to \Gamma(\Lambda^{\bullet+1} T^* M \otimes E)$, which firstly should be a differential operator of order 1 and secondly should give the cohomology $$ H^k(\Gamma(\Lambda^{\bullet} T^* M \otimes E)) \cong H_{\text{dR}}^k(M) \otimes_{\mathbb{R}} V.$$
I don't necessarily need this differential to have anything to do with the de Rham differential on $M$ directly, and you're free to use connections. Is there a more or less well-known candidate fulfilling this property? Or is this doomed to fail if we do not allow for flat connections? Also if the question is underspecified in some way, let me know.
The reason I believe a differential like this should exist is because, by my understanding, it should show up in the last step of Theorem 2.4.1a in Fuks' book "Cohomology of infinite-dimensional Lie algebras". The details are omitted, but I think a differential as I describe needs to exist in some way for their result to hold. If needed I can give some more details.