Let $k$ be a field of characteristic $0$ und let $X$ be a del Pezzo surface over $k$. Note that $X$ may not have points.
Let us consider $N:=\ker(\mathrm{Br}(k) \rightarrow \mathrm{Br}(k(X))$.
Question 1: Under which circumstances depending on $k$ or $X$, is $N$ generated by one element?
From the Hochschild-Serre spectral sequence, we obtain the infamous sequence
$0 \rightarrow \mathrm{Pic(X)} \rightarrow \mathrm{Pic}(\overline{X})^{\mathrm{Gal}(\overline{k}/k)} \rightarrow \mathrm{Br}(k)$.
The last map assigns a Brauer class to each element in $\mathrm{Pic}(\overline{X})^{\mathrm{Gal}(\overline{k}/k)}$ , which I will call a Tits algebra. Clearly, depending on the rank of $\mathrm{Pic}$, there may be several Tits algebras. It is possible that $X$ has non trivial Tits algebras. Also they may be all isomorphic.
We denote the Severi-Brauer variety of a central, simple algebra $A$ by $\mathrm{SB}(A)$.
Question 2: Assume that $X$ has none trivial Tits algebras. How do they change over $k(X)$ ?
Question 3: Assume $X$ has only one Tits algebra $A$, which is not trival and let us assume that $N$ is generated by one element. Does $N$ become trivial over $k(\mathrm{SB}(A))$? What is the general relation between $A$ and the generator of $N$.