Let $M$ be a compact smooth Riemannian manifold. Then it admits a triangulation, i.e. a finite simplicial complex $K$ which is homeomorphic to $M$. Any such simplicial complex carries a natural metric - the path metric which concides with the usual metric on each simplex. Can we always choose $K$ so that with this path metric, it is bilipschitz equivalent to $M$ with the metric coming from its Riemannian structure?