# Hensel lemma and rational points in complete noetherian local ring

Let $$A$$ be a complete noetherian local ring and $$\mathfrak{m}$$ be its maximal ideal.

If we have several polynomials $$f_i \in A[X_1, \dots, X_m]$$ which have a common zero $$x_n$$ in $$A/\mathfrak{m}^n$$ for any $$n$$, then must they have a common zero in $$A$$? In other words, if we have a scheme $$X$$ finite type over $$A$$, does $$X(A/\mathfrak{m}^n) \not= \varnothing \ \forall n$$ imply $$X(A) \not= \varnothing$$?

This seems an easy question, but the main problem is compatibility for $$x_n$$. If $$X$$ is smooth we conclude by Hensel lemma.

• If $$k=A/\mathfrak{m}$$ is finite then it's true because inverse limit of non-empty finite sets is non-empty.
• If $$A$$ is a DVR then we know from a general Hensel lemma from "RATIONAL POINTS IN HENSELIAN DISCRETE VALUATION RINGS" by MARVIN J. GREENBERG.
• If $$k=A/\mathfrak{m}$$ is algebraically closed and uncountable, it is also true by considering constructible topology and the inverse limit of non-empty compact Hausdorff spaces is non-empty.

What about general case? Here we assume that $$A$$ is a complete noetherian local ring, but this also covers the excellent Henselian local ring case because of Artin approximation.

• If you assume $X$ to be smooth over the punctured spectrum of $A$, then the answer is yes by Thm. 1 in Elkik's "Solutions d'équations a coefficients dans un anneau hensélien" (the role of smoothness is to ensure that the assumption which concerns the ideal $H_B$ there is met). A similar result in a non-Noetherian setting is Lemma 5.4.8 ff in Gabber, Ramero "Almost ring theory". Also, it would be be interesting to have a non-Noetherian result of this sort beyond principal ideals, e.g., for finitely generated weakly proregular ideals (this would, in particular, recover Elkik's result)... – Kestutis Cesnavicius Dec 11 '18 at 9:01
• This is true in general, by the "strong approximation property" due essentially to Popescu. See the survey arxiv.org/abs/1506.04717v4 by Guillaume Rond, or the Bourbaki talk by Teissier numdam.org/item/SB_1993-1994__36__259_0 – Laurent Moret-Bailly Dec 11 '18 at 15:03
• @LaurentMoret-Bailly Theorem $3.16$ in this good survey solves the problem, and your work shows Theorem $3.16$ implies $A$ is an excellent Henselian local ring, so basically that's all we can say. I didn't notice that strong arrpoximation property before, thank you. – zzy Dec 11 '18 at 16:14