5
$\begingroup$

Given a D-module $\mathcal{M}$ on $\mathbb{C}^n$, its Fourier transform $\widehat{\mathcal{M}}$ is equal to $\mathcal{M}$ as a set, but its module structure over $\mathbb{C}[x_1,...,x_n,\partial_1,...,\partial_n]$ is given by $$x_i \cdot m \ = \ -\partial_i m \ \ \ \text{ and } \ \ \ \partial_i \cdot m \ = \ x_im$$ This definition comes from how the classical Fourier transform acts on ODEs, see *.

But now consider a compact Lie group $G$. For each $\rho \in \widehat{G}$ there is a ``Fourier transform'' $$\text{functions on }G \ \longrightarrow \ \mathbb{C}$$ $$f \ \longrightarrow \ \int f(g)\rho(g) dg$$

Is there a ``Fourier transform'' of D-modules on $G$ (or maybe some flag variety of $G$) associated to each $\rho \in \widehat{G}$?

The reason I suspect this might be true is that, though one might initially protest that this is probably an affine phenonemon, Lie groups (or rather their flags) are D-affine.

$$\text{}$$ $$\text{}$$

*On $\mathbb{C}$, the Fourier transform take an ODEs with polynomial coefficients $$a_n(x)\partial^nf+\cdots+a_0(x)f \ = \ 0$$ to another such ODE $$a_n(-\partial)k^n\widehat{f}+\cdots+a_0(-\partial)\widehat{f}\ = \ 0$$ because the Fourier transform of $x^m$ is $\delta^{(m)}(k)$. The same is true for $\mathbb{C}^n$.

$\endgroup$
2
  • $\begingroup$ Just a remark: D-modules on $G$ may not possibly encode representations of $G$, since D-modules should better be thought of as locally constant functions. Characters of representations of $G$ are of quite different nature. $\endgroup$
    – Wille Liu
    Commented Apr 27, 2018 at 20:55
  • $\begingroup$ What seem to be more reasonable to me are coherent sheaves. For example, Bezrukavnikov, ams.org/journals/ert/2003-007-01/S1088-4165-03-00158-4/… $\endgroup$
    – Wille Liu
    Commented Apr 27, 2018 at 21:15

0

You must log in to answer this question.

Browse other questions tagged .