# Non-vanishing modular forms

Prompted by this MO question, I have the following question about modular forms which do not vanish on the upper-half plane.

Q1. Let $N \geq 1$ be an integer and let $\Gamma(N)$ be the principal congruence subgroup of $\mathrm{SL}_2(\mathbf{Z})$ of level $N$. What is the minimal weight $k \geq 1$ such that there exists a meromorphic modular form of weight $k$ on $\Gamma(N)$ which does not vanish on the upper-half plane?

Note that I only require the modular form to be meromorphic at the cusps, so the set of such weights is of the form $k_0 \mathbb{N}$ for some $k_0 \geq 1$. Moreover, the example of the modular discriminant $\Delta$ shows that $k_0$ divides 12. Jeremy Rouse's answer shows additionally that if $12$ divides $N$ then we have $k_0=1$.

Another motivation for asking this question is given by universal elliptic curves. If $E/S$ is an elliptic curve over an arbitrary scheme $S$, then the $12$-th power of the line bundle $\omega_{E/S}$ on $S$ is trivial, see e.g. this MO post by Brian Conrad. In the case $S=Y(N)$ and $E=E(N)$ is the universal elliptic curve over $Y(N)$ with $N \geq 3$, then I think the order of $\omega_{E(N)/Y(N)}$ in the Picard group of $Y(N)$ coincides with the integer $k_0$ introduced above, because weight $k$ modular forms correspond to sections of $\omega_{E(N)/Y(N)}^{\otimes k}$, and non-vanishing modular forms correspond to trivializations.

Q2. Let $N \geq 3$ be an integer. Let $\mathcal{Y}(N)$ be the modular curve over $\mathbf{Z}[1/N]$ representing the moduli problem of elliptic curves with full level $N$ structure as in Katz-Mazur. Let $\mathcal{E}(N)$ be the universal elliptic curve over $\mathcal{Y}(N)$. What is the order of $\omega_{\mathcal{E}(N)/\mathcal{Y}(N)}$ in the Picard group of $\mathcal{Y}(N)$?

Note that Q1 makes sense for arbitrary congruence subgroups, and Q2 makes sense as soon as the corresponding moduli problem is representable. I would be interested as well by answers to Q1 and Q2 for congruence subgroups other than $\Gamma(N)$.