Let $(R, \mathfrak{m})$ be a local domain and $x$ is a basic element of $\mathfrak{m}$, that is $x \in \mathfrak{m} \setminus \mathfrak{m}^2$. Let $P$ be a prime ideal containing $x$. Is it true that $x$ is a basic element in $R_P$?

**Edit:** By the Mohan answer, the question has negative answer. In fact, I am interested in a stronger property for $x$. Suppose $\dim R = d$ and $(x_1, \ldots, x_d)$ be a minimal reduction of $\mathfrak{m}$ (here we assume that the residue field is infinite). Let $x = x_1$, we have $x$ is a basic element of $R$. Let $P$ be a prime ideal containing $x$. The question now as follows:

**Question:** Is it true that $x$ is a basic element in $R_P$? Is it an basic element of a minimal reduction of $P R_P$.