For a complete noncompact Riemannian manifold with sectional curvature positive, it is diffeomorphic to $\mathbb{R}^n$ by known result. Choose a point $p$ on the manifold, is it possible that the distance function $d(p, \cdot)$ has a sequence of critical points going to the infinity of the manifold?

$\begingroup$ Sectional curvature is positive or nonpositive? $\endgroup$– MahdiAug 6 '17 at 11:12

$\begingroup$ strictly positive sectional curvature. $\endgroup$– mmaatthhAug 6 '17 at 11:45
Yes, it is a classical result.
Let $q_1,\dots,q_n$ be a sequence of critical points such that $$q_{n+1}p\ge 2\cdot q_np.$$ By Toponogov's comparison, $$\measuredangle [p\,^{q_i}_{q_j}]\ge \tfrac\pi3.$$ Hence we get a bound on $n$.

$\begingroup$ What about $3$dim complete Riemannian manifold with $Rc> 0$? SchoenYau had proved it is diffeomorphic to $\mathbb{R}^3$, is it also true that all critical points with respect to a fixed point $p$ is in a compact set?@Anton Petrunin $\endgroup$– mmaatthhAug 7 '17 at 0:00