In a new survey on $E_8$, namely
Skip Garibaldi - E8 the most exceptional group
, the author gives an example (Example 8.4., page 15) on how to construct a group of type E8 with a prescribed Tits-Index. This construction was actually invented by Tits and bears his name..
From the inclusion of $F_4 \subset E_6 \subset E_8$, after applying $H^1(k,-)$, a isotropic group of type $E_8$ with semi simple anisotropic kernel of type $E_6$ arises from an Albert Algebra $A$, which is a $F_4$ torsor (meaning an element of $H^1(k,F_4)$). (Note that this example serves to explain some properties of the Rost invariant of this $E_8$, but we want to focus on the construction itself.)
We will remember this for later and call it #Above
In the Paper
J. Tits - Stronger inner anisotropic forms of simple algebraic groups
,on the last page the author gives an example of a group of type $E_7$ having semi simple anisotropic kernel $D_5 \times A_1$, or in Tits's notation is of index $E^{48}_{7,1}$, meaning the vertex $6$ is circled.
He writes:
"..[27, Proposition 5] shows that groups with this index are classified by anisotropic quadratic forms $q$ in $10$ variables, whose invariant $c(q)$ is a division quaternion algebra."
1.Does he mean classified as constructed like in #Above ?
If he means like in #Above:
1.1.Is a group with that index constructed by choosing such a $q$, looking at $SO(q)$, which is of type $D_5$ and adjoint, noticing that $D_5\subset D_6 \subset E_7$ and applying $H^1(k,-)$?
What is confusing to me is that the anisotropic kernel of the resulting $E_7$ is not just $D_5$ but $D_5 \times A_1$. But on the other hand $D_5$ can never occur as anisotropic kernel, so it might all fit together.
2.What is known about the quadratic forms $q$?
I ponder they have splitting pattern $(1,2,2)$, after analyzing the more isotropic Tits-Indexes and taking into account Vishik's classification of splitting patterns.