**Motivation:** I am studying the graph isomorphism problem. I am trying to construct a partitioning method to reduce search cases .

**Construction:**
$G$ is an $r$ regular graph, $k$ connected (not a complete, cycle graph). A vertex of $G$ is $x_1$.
All vertices which are not adjacent to $x_1$ create a sub-graph $C_1$.
All vertices adjacent to $x_1$ create a sub-graph, $ D_1 $.
A vertex of $D_1$ is $x_2$.

Using same method, based on adjacency of $x_2$ , $D_1$ can be divided.

All vertices which are not adjacent to $x_2$ create a sub-graph $C_2$.

All vertices adjacent to $x_2$ create a sub-graph, $ D_2 $. In general, $ D_{y-1} $ is a graph and can be divided/partitioned into 2 sub-graphs $C_y, D_y $.

At this stage, let me restrict the problem for simplicity of computation. Restrictions are:

$C_y, D_y $ are $s_y , t_y>0 $ regular graphs respectively for all iteration $y$

$C_y, D_y $ cannot be complete bipartite graph (utility graph), complete graph or disjoint union of complete graphs.

So, $ D_{y-1} $ is a $t_{y-1}$ regular graph and can be divided/partitioned into 2 sub-graphs $C_y, D_y $. $C_y, D_y $ are $s_y , t_y $ regular graphs respectively (given condition).

$G$ can be divided/partitioned a maximum of $\log_2(|G|)$ times, using this dividing process recursively.

**Matrix representation :**
$A$ is an adjacency matrix of an $r$-regular graph $G$.
The matrix A can be divided into 4 sub-matrices based on adjacency of vertex $x_1 \in G$.
$A_x$ is the adjacency matrix of the graph $(G-x_1)$, where $C_1$ is the adjacency matrix of the graph created by vertices which are not adjacent to $x_1$, and $D_1$ is the adjacency matrix of the graph created by vertices which are adjacent to $x_1$. $C_1,D_1$ are sub-graphs (regular) of graph $G$, $|C_1|>|D_1|$ where $|C_1|,|D_1|$ are total vertices number of graphs $C_1,D_1$ respectively.
$$ A_x
=
\left( \begin{array}{ccc}
C_1 & E_1 \\
E_1^{T} & D_1 \\
\end{array} \right)
$$

Again, this process can be done recursively, where $A_{y+1}=D_y$, $y=$ iteration number of the recursive process. $$ A_yx = \left( \begin{array}{ccc} C_y & E_y \\ E_y^{T} & D_{y} \\ \end{array} \right) $$

$A_x$(=$A_1x$) is the matrix of 1st iteration, for 2nd iteration, $A_x$ matrix would be $A_2x$.

**How restrictions can be lifted later:**

If $C_y, D_y $ are not regular graphs for iteration $y$, then $C_y $ or $ D_y $ can be divided into regular sub graphs where each sub-graph has same valency. It is well known, from GI perspective, that Irregular graph is easier to partition than regular graph to determine GI. So, if irregular $C_y , D_y $ will not increase search cases .

$C_y, D_y $ cannot be complete bipartite (utility graph), complete or disjoint union of complete graphs but GI of these graphs are easier.

*Both conditions can be lifted.*

**Claim:**

*It is not possible to have an $E_y$ matrix as a zero matrix, i.e., it is not possible to have disconnected sub-graphs $C_y,D_y$ under the given conditions that $G$ is $k$ connected $r$ regular and $C_y , D_y$ are always regular (which are not complete bipartite, complete graph nor disjoint union of complete graphs) graphs in this recursive process.*

** Argument:** see Possibility of Disconnected Subgraphs of a $k$ Connected $r$ regular Graph under a given condition and Decomposition of a regular graph and connected subgraphs this post.

**Question: Is it possible to partition a graph always as described above?**

**Edition 1 :** V.A.Taskinov, Regular subgraphs of regular graphs. Sov.Math.Dokl.26(1982), 37-38 .
In this paper he proved the following : Let $0<k<r$ be positive odd integers. Then every $r$-regular graph contains a $k$-regular subgraph (here, the graph need not be simple).