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Apr 13, 2017 at 12:57 history edited CommunityBot
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Aug 31, 2015 at 17:40 comment added Todd Trimble Migrating to Theor. Comp. Sci. on request of OP...
Aug 31, 2015 at 17:40 history edited Todd Trimble CC BY-SA 3.0
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Aug 27, 2015 at 3:53 comment added Michael @BrendanMcKay , The 'Construction' described above can be seen as an individualization technique. Is there any individualization in current literature as describe above in 'Construction' ? Is it actually a k-dimensional Weisfeiler-Lehman method?
Aug 7, 2015 at 18:43 comment added Sebi Cioaba The strongly regular graph on 416 vertices described in this paper arxiv.org/abs/1305.2584 has a property similar to what is discussed here.
Aug 5, 2015 at 17:25 history edited Michael CC BY-SA 3.0
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Aug 1, 2015 at 3:36 comment added Brendan McKay @Jim, Nobody knows. However it is interesting that the fastest known algorithm for strongly regular graphs is faster than the fastest known for general graphs, see ieeexplore.ieee.org/xpl/…
Aug 1, 2015 at 2:08 comment added Michael @BrendanMcKay , Sir, you said , that such graphs are not the hardest graphs for the isomorphism problem, can their isomorphism be determined less than quasipolynomial time?
Aug 1, 2015 at 2:05 comment added Brendan McKay @vzn The existing practical approaches have trouble when there are inequivalent vertices that are hard to distinguish. Regularity is a step in that direction but not enough by itself. On the other hand, very restricted classes of graphs often allow specially tailored treatment. Nobody really knows how to define the "hardest" class of graphs.
Jul 31, 2015 at 23:48 history edited Michael CC BY-SA 3.0
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Jul 31, 2015 at 23:24 comment added vzn @Brendan can you cite something that would point to "the hardest graphs for the isomorphism problem"? arent they thought to be regular? thx!
Jul 31, 2015 at 19:21 history edited Michael CC BY-SA 3.0
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Jul 29, 2015 at 14:49 history edited Michael
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Jul 29, 2015 at 9:01 comment added Michael @BrendanMcKay , Sir, I was/am planing to generalize this class later.For example, Without restriction 2, there will be complete $C_y, D_y$ graphs, complete graphs are not hardest for GI, I guess.
Jul 29, 2015 at 2:52 comment added Brendan McKay Your conditions indicate that your graph is strongly regular. If C1 and D1 have the same properties, then you have a highly restricted class of strongly regular graphs, see sciencedirect.com/science/article/pii/002186937890220X . It is most unlikely that such graphs are the hardest graphs for the isomorphism problem.
Jul 29, 2015 at 2:04 history edited Michael
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Jul 29, 2015 at 1:59 history asked Michael CC BY-SA 3.0