2
$\begingroup$

thank you for spending time on the following question.

In [1] Khovanov and Rozansky categorifized $sl_n$ version of HOMFLY Polynomial, in page 11, they mention that what they defined in [1] is equivalence to what Khovanov "original" defined in [2] and give a short argument:

(I) For a closed link diagram $\Gamma$ with marked point, its cohomology group $H(\Gamma)$ are isomorphic to $A_2^{\otimes k}$, where $A_2$ is the cohomology ring of 2-sphere and k the number of circles in the diagram given by deleting all wide edges of $\Gamma$

(II)The equivalence of n=2 and [2] follows easily from observation.

I wonder that anyone could tell me how to show the equivalence in detail or give me some hint for proving (I) and (II). Even in n=2, I still find unable to understand the factorization for a wide edge with potential $w_t=x_1^{n+1}+x_2^{n+1}-x_3^{n+1}-x_4^{n+1}$.

[1]Matrix Factorizations and Link Homology, Khovanov, Rozansky

[2]A Categorification of the Jones Polynomial, Khovanov

$\endgroup$

1 Answer 1

2
$\begingroup$

http://www.worldscientific.com/doi/abs/10.1142/S0218216514500576

In the following paper, the author give a explicit isomorphism.

Mark C. Hughes, A note on Khovanov–Rozansky sl2-homology and ordinary Khovanov homology, J. Knot Theory Ramifications, 23, 1450057 (2014)

$\endgroup$
0

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .