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Suppose we have a bounded convex open set $\Omega$ in $\mathbf{R}^n$,and a sequence of convex functions $P_n$ such that $||P_n||_{L^2(\Omega)}\leq C\forall n$.Is it possible to find a subsequence which is uniformly convergent on each compact subsets of $\Omega$? Of course the problem boils down to ask if it is possible to estimate the $L^{\infty}$ bound of a convex function in the interior by its global $L^2$ bound.

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Yes. If $K \subset \Omega$ is compact, let $\text{dist}(K, \Omega^c) > r > 0$. Then for any $p \in K$ and convex function $f$, $f(p)$ is bounded above by the average of $f$ over the ball of radius $r$ centred at $p$, and thus by a constant (depending only on $r$) times $\|f\|_{L^2(\Omega)}$.

For a lower bound, note that if $Q$ is a uniform random variable on the ball $B_r(p)$ of radius $r$ centred at $p$, $(Q+p)/2$ is uniform on $B_{r/2}(p)$, and $f(p) \ge 2 f((Q+p)/2) - f(Q)$, so $$f(p) \ge \dfrac{2}{m(B_{r/2}(p)} \int_{B_{r/2}(p)} f - \dfrac{1}{m(B_r(p))} \int_{B_r(p))} f \ge - C(r) \|f\|_{L^2(\Omega)}$$

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  • $\begingroup$ Thanks a lot for your answer ! I realized later one can also argue this by contradiction,but your solution is much simpler. $\endgroup$ Commented Jan 8, 2015 at 14:38

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