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Consider an n dimensional Riemannian manifold with boundary. Let $\Phi$ be a complex valued smooth function defined in M. Does there exist a NONE VANISHING complex valued function $u$ that solves the following complex pde subject to some boundary condition. $ \nabla • ( u \nabla \Phi) = 0 $ I seem to have a little trouble with this due to functions being complex valued. Thanks,

Comment: So far I have been able to show that if the real and imaginary parts of $\Phi$ Satisfy an integrability condition then one can always find a solution $u$ subject to any boundary condition and enforce u to be non vanishing... But I suspect I do NOT need this integrability condition...

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  • $\begingroup$ Since you are only asking for local solvability, why are you specifying that the Riemannian manifold has a boundary without specifying what the boundary conditions are? $\endgroup$ Commented Dec 5, 2014 at 19:22
  • $\begingroup$ You are right, I have corrected the statement $\endgroup$
    – Ali
    Commented Dec 5, 2014 at 19:27

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Let me answer to the local solvability question in the $C^\infty$ category. Take a complex-valued vector field $Z=X+iY, X,Y$ real-valued vector fields such that $Z$ is always non-zero (a "principal-type" condition). There are some terrible pathologies for some very simple examples as the Hans Lewy vector field in $\mathbb R^3$, $$ \mathcal L=\partial_{x_1}+i\partial_{x_2}+i(x_1+ix_2)\partial_{x_3}. $$ For "most" functions $f$ (in the Baire category sense), the equation $\mathcal Lv=f$ does not have a distribution solution, even locally.

There is an iff local solvability condition for these principal type vector fields $Z$, the so-called Nirenberg-Treves condition $(P )$. It is not so easy to write it down in general but the following case is a significant illustration: take in $\mathbb R^2$, $$ Z=\partial_{x_1}+ib(x_1, x_2)\partial_{x_2}. $$ Then $Z$ is locally solvable near $0\in \mathbb R^2$ iff there exists a neighborhood of $0\in \mathbb R^2$ such that $$ x_1\mapsto b(x_1, x_2) \text{ does not change sign for any given $x_2$ near 0.} $$ It turns out that this condition has an invariant expression.

Simple examples of non-locally solvable operators are $$ \partial_{x_1}\pm ix_1\partial_{x_2},\quad \partial_{x_1}\pm ix_1^{2k+1}\partial_{x_2}, \quad\text{since $x_1^{2k+1}$ changes sign at $0$,} $$ and simple examples of locally solvable operators are $$ \partial_{x_1}\pm i\partial_{x_2},\quad, \partial_{x_1}\pm ix_1^{2}\partial_{x_2},\quad \partial_{x_1}\pm ix_1^{2k}\partial_{x_2}, \quad\text{since $x_1^{2k}$ does not change sign.} $$

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  • $\begingroup$ Thanks for mentioning the Nirenberg-Treves Condition and for the examples. $\endgroup$
    – Ali
    Commented Dec 6, 2014 at 0:31

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