Let $A=E+\sqrt{-1}B$, where $E=diag\{0,1,\cdots,1\}$, $B$ is a real symmetric matrix. Let $A^*$ denote the adjoint matrix of $A$, i.e. $AA^*=\det A\cdot I$. I hope the real part of adjoint matrix ${\rm Re}A^*$ is nonnegative. The question is that should I add what kind of condition on $B$ to guarantee ${\rm Re}A^*\geq 0$.
1 Answer
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A sufficient condition is as follows. Let $S=Re(Adj(A))$. Choose the diagonal of $B$ positive and large enough. One has
For $n=4p$: $S<0$. For $n=4p+1$, $S>0$.
For $n=4p+2$: $S>0$. For $n=4p+3$, $S<0$.