9
$\begingroup$

A completely regular topological space $(X,\tau)$ is a $P$-space, if every $G_\delta$-subset of $X$ is open (i.e $\tau$ is closed under countable intersections).

A topological space $X$ is linearly Lindelöf if every open cover of $X$ which is linearly ordered by the subset relation has a countable subcover.

Is there a linearly Lindelöf non-Lindelöf $P$-space?

Improve this question
$\endgroup$
4
  • 1
    $\begingroup$ math.stackexchange.com/questions/474376/… Please, do not double post your question on MSE and on MO. If you see that your question is still without an answer on one of these sites after a while, you can still post it on the other site. $\endgroup$
    – Stefan Hamcke
    Commented Aug 23, 2013 at 15:02
  • 5
    $\begingroup$ I don't know why people are voting to close this question. Perhaps at least one of the voters could give a reason? $\endgroup$
    – Ramiro de la Vega
    Commented Aug 24, 2013 at 0:36
  • 5
    $\begingroup$ Robson: In Arhangelski-Tkachenko's book, the following is listed as an open problem: "is every linearly Lindelof P-group Lindelof?". I've also seen "Is the product of two linearly Lindelof P-spaces linearly Lindelof?" listed as open, so my guess is that your question is also open, but I'm not sure. $\endgroup$
    – Ramiro de la Vega
    Commented Aug 24, 2013 at 0:41
  • $\begingroup$ Is it at least true that every discretely Lindelof P-space is Lindelof? "Discretely Lindelof" means "the closure of every discrete set is Lindelof". It's not too hard to see that every discretely Lindelof space is linearly Lindelof. $\endgroup$
    – Santi Spadaro
    Commented Nov 8, 2017 at 18:23

1 Answer 1

Reset to default
6
$\begingroup$

It was shown by A.K. Misra in "A topological view of $P$-spaces" that any regular $\aleph_1$-Lindelöf $P$-space is normal (see Corollary 4.6). Also, it is not hard to see that any linearly Lindelöf space must be $\aleph_1$-Lindelöf.

Finding a normal linearly Lindelöf non-Lindelöf space is a very well known open problem in general topology. So now I´m pretty sure that your question is also open.

Edit: As pointed out by Robson (see comment below), the notion of $\aleph_1$-Lindelöf used by Misra in his paper doesn't correspond to modern terminology. So I don´t know if a regular linearly Lindelöf $P$-space must be normal. However the following is question 486 in "Open problems in topology II":

(Arhangel´ski) Is the product of two linearly Lindelöf $P$-spaces Lindelöf?

So I still think that the OP´s question is open, since product of two Lindelöf $P$-spaces is Lindelöf (so it is the same question after all).

Improve this answer
$\endgroup$
2
  • 1
    $\begingroup$ Corolllary 4.6: Every regular $\aleph_1$-Lindelöf $P$-space is paracompact, hence normal. By the context, I think "$\aleph_1$-Lindelöf" in this corollary means "$L(X)\leq\aleph_1$". Note that if the corollary 4.6 was true for current definition of "$\aleph_1$-Lindelöf" then the question would be answered because: linearly Lindelöf + regular + paracompact $\Rightarrow$ Lindelöf $\endgroup$
    – Robson Figueiredo
    Commented Aug 26, 2013 at 17:59
  • $\begingroup$ @Robson: I think you are right. I´ll edit my "answer". $\endgroup$
    – Ramiro de la Vega
    Commented Aug 26, 2013 at 18:33

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .