0
$\begingroup$

I am trying to figure out with Drindfel's Opers. Let us consider Lie group $G$ and $G$ -- bundle $\mathcal{F}$ on the smooth algebraic curve $Y$. Can anybody help me and clarify definition of the $\mathcal{F}$ -- twist of $\mathfrak{g}$ where $\mathfrak{g}$ is Lie algebra of $G$.

$\endgroup$
2
  • $\begingroup$ The product $\mathcal{F} \times \mathfrak{g}$ has a natural $G$-equivariant structure by the right action on $\mathcal{F}$ and the adjoint action on $\mathfrak{g}$. The twist is given by fppf descent. $\endgroup$
    – S. Carnahan
    Commented Aug 1, 2013 at 22:37
  • $\begingroup$ I've made out missing constructions by virtue of your comment. $\endgroup$
    – quantum
    Commented Aug 3, 2013 at 16:40

0

You must log in to answer this question.

Browse other questions tagged .