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In my understanding, random variable is a measurable function from a probability space to a measurable space. Suppose $X$ is a random variable from $(A, \sigma_{A},P_A)$ to $(B,\sigma_{B})$. And $Y$ is a random variable from $(B, \sigma_{B}, P_B)$ to $(C, \sigma_{C})$.

Then $Y(X)$ is a random variable from $A$ to $C$. The problem is here, in the space $B$, we can induce probability from $A$ by random variable $X$, s.t., $P_{B}'(I) = P_A(X^{-1}(I))$. Also, random variable $Y$ use the probability measure $P_B$, then if we want to calculate the probability distribution of $Y(X)$, what probability should be used, $P_B'$ or $P_B$, or both?

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$Y(X)$ doesn't mean anything. You can't define the composition of random variables. What you can do is compose a random variable $X$ by a measurable function $f$ (provided the $\sigma$ algebras are the same) : $f(X)$.

So in your example, there are two different objects, measurable functions and random variables :

-the measurable functions $f$ from $(A,\sigma_A)$ to $(B,\sigma_B)$ and $g$ from $(B,\sigma_B)$ to $(C,\sigma_C)$. Since $B$ uses the same $\sigma$-algebra, the function $g \circ f$ is measurable from $(A,\sigma_A)$ to $(C,\sigma_C)$.

-the random variable when you add a probability distribution to the measurable spaces. So if you add $P_A$ to $(A,\sigma_A)$, the measurable function $f$ from $(A,\sigma_A)$ to $(B,\sigma_B)$ induces a random variable we can write $X$. Now since we also have a measurable function $g \circ f$ from $(A,\sigma_A)$ to $(C,\sigma_C)$, it also induces another random variable that we can write $X'$ or more usually $g(X)$. And if you add $P_B$ to $(B,\sigma_B)$, function $g$ induces a random variable we'll write $Y$.

But the composition $Y(X)$ doesn't makes any sense.

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  • $\begingroup$ Thank you for your answer. Perhaps, I shouldn't associate probability to a random variable but define probability measure for some $sigma$-algebra instead. If I define random variable $Y$ in $(B, \sigma_B)$, I should use the probability induced by $X$ when I intend to use the form like $Y(X)$. BTW, when $X$ is the parameters in $Y$'s distribution function, it would be fine to define another probability measure on $(B, \sigma_B)$ for $Y$. $\endgroup$
    – itsuper7
    Commented Sep 17, 2012 at 14:08
  • $\begingroup$ Well, you could define a random variable this way and write it $X$ or $Y$, but this is already defined as a measurable function, and it is usually written with small letters life $f$ or $g$ :) So if you want to be understood, you should speak of $g \circ f$ (measurable function), or $g(X)$ for the random variable, but not $Y(X)$. $\endgroup$
    – Adrien
    Commented Sep 19, 2012 at 8:36
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    $\begingroup$ I have no idea why one cannot compose a random variable with a random variable. $\endgroup$ Commented Apr 23 at 17:08
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    $\begingroup$ I'd have written $Y\circ X$ rather than $Y(X),$ in this context at least, but you are wrong to say you cannot compose random variables. $\endgroup$ Commented Apr 23 at 21:25
  • $\begingroup$ @MichaelHardy One should really think of random variables as being defined modulo null sets. In that context, composing two random variables genuinely doesn't make sense in general. $\endgroup$ Commented Apr 23 at 22:01
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Think of the set $A$ that underlies the probability space $(A, \sigma_A,P_A)$ as some vast population to each of whose members you assign values of various functions whose domain is $A$: their height in inches, their income, their weight, how far they are from London, etc. One of those functions is the random variable $X.$ The measure $P'_B,$ whose domain is $\sigma_B$ is the one you care about and are likely to know about; all those myriad other random variables whose domain is the population $A$ need not concern you for the purposes of this problem. Thus you use what you know about $P'_B$ to find the probability distribution of $Y\circ X.$

Thus if you're told the distribution of IQ scores is $$ \frac1 {\sqrt{2\pi\,}}\exp\left( -\frac12 \left( \frac{x - 100}{15}\right)^2 \right) \, \frac{dx}{15} \tag 1 $$ and you want the distribution of the square of IQ scores, you use the information on line $(1)$ above.

That is typical in practice.

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