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About fundamental theorem of algebra, there is a large collection different demonstrations.

I ask: is there some proof that avoids AC (choice axiom)?

In a general topos (with natural number object) there are the two constructions of real numbers (generalizations of the classical Dedekind and Cauchy constructions) that are different.

In ZF theory, are the Dedekind and Cauchy constructions different? (In the "Cauchy" reals, operates on a real number $r$ through a choice of a Cauchy sequence converging to $r$.)

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    $\begingroup$ It is a theorem of ZF that any two complete (in the order sense) ordered fields are isomorphic. In particular, the complete ordered fields constructed by the Dedekind and Cauchy methods are isomorphic. AC is not needed for any of this. $\endgroup$ Commented Jun 21, 2012 at 21:35
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    $\begingroup$ Gerald, that's an interesting remark. I believe that this fact is also intuitionistically valid. In fact, in a topos, the Cauchy and Dedekind reals are the same precisely when the Cauchy reals are ordered... $\endgroup$ Commented Jun 21, 2012 at 23:03

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The fundamental theorem of algebra is, unless I miscounted quantifiers, a $\Pi^1_2$ sentence of second-order arithmetic and therefore absolute between the full universe and Gödel's constructible universe by the Shoenfield absoluteness theorem. So, since it's provable in ZFC, it is necessarily provable in ZF as well.

I believe, though, that this metamathematical argument can be avoided, because I don't see any serious use of the axiom of choice in usual proofs by methods of analysis and (plane) topology.

The Dedekind and Cauchy constructions of the reals are equivalent in ZF; no choice is needed. Although AC is often involved when one wants to prove general results about sequences of reals, in the present situation one only needs to consider sequences of rationals. So one can fix an enumeration of the rationals and thereafter, whenever a rational needs to be chosen, taking the first suitable one in the enumeration.

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Regarding Cauchy and Dedekind reals. The fact that every Dedekind real has a Cauchy representation is provable in very weak systems of intuitionistic analysis. The converse fact that every Cauchy real has a Dedekind representation is equivalent to the Weak König Lemma (WKL) — that every infinite tree of $\lbrace0,1\rbrace$-sequences has an infinite path. (See note.) This very weak form of König's lemma is provable in ZF, so there is no difference between Cauchy reals and Dedekind reals in ZF.

Breaking this down further, the ability to compare a Cauchy real to a given rational number is equivalent to the Lesser Limited Principle of Omniscience (LLPO), which can be formulated as follows $$\lnot(\exists n A(n) \land \exists n B(n)) \rightarrow (\forall n \lnot A(n) \lor \forall n \lnot B(n)),$$ where $A(n)$ and $B(n)$ are simple decidable statements (e.g., primitive recursive predicates). Note that LLPO is a consequence of the Law of Excluded Middle, and therefore true in every classical system such as ZF, but not necessarily in intuitionistic systems such as topoi. To extract a Dedekind cut from a Cauchy real, it is necessary to simultaneously compare a real with every rational number, so we need to repeat LLPO countably many times. WKL is precisely equivalent to countably many repetitions of LLPO. In set theory and topos theory, such repetitions come for free through comprehension. So the only thing that can prevent every Cauchy real to have a Dedekind cut in a topos is the failure of LLPO.


This is not quite true as I originally stated it. It is the existence of a "uniform method" for converting Cauchy reals into Dedekind reals which is equivalent to WKL. In classical systems, one can get around the uniformity requirement through clever use of the Law of Excluded Middle. In weak classical systems such as RCA0 one can prove that every Cauchy real has a Dedekind cut by providing separate methods for rational and irrational numbers, thus sweeping a lot of the computation cost in deciding whether a real is rational or not. The equivalence with WKL is recovered when one asks to simultaneously find Dedekind cuts for an infinite sequence of Cauchy reals, as demonstrated by Hirst [Representations of reals in reverse mathematics, Bull. Pol. Acad. Sci. Math. 55 (2007), 303–316; MR2369116].

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  • $\begingroup$ Another clarification, by "comparing a real with a rational," I mean comparison in the weak sense, $a \leq b \lor a \geq b$; strong comparison, $a \lt b \lor a = b \lor a \gt b$, is equivalent to the stronger Limited Principle of Omniscience (LPO). $\endgroup$ Commented Jun 21, 2012 at 22:42
  • $\begingroup$ I'm very confused. You're claiming that every Dedekind real is a Cauchy real but that the converse requires WKL. But every text I've seen on the subject (e.g., this and this, or chapter 5 of Troelstra & van Dalen's Constructivism in mathematics, or section D.4.7 of Johnstone's Elephant) goes the other way around: AFAIK, in a topos, or in CZF, every Cauchy real is Dedekind but the converse need not hold. Dedekind reals need not be comparable with every rational. $\endgroup$
    – Gro-Tsen
    Commented Nov 28, 2022 at 9:56
  • $\begingroup$ @Gro-Tsen I think there is a bit of ambiguity when defining Dedekind-cuts, namely whether they are decidable or just enumerable sets. The former choice causes problems when considering the Dedekind-cut-representation of a rational number. $\endgroup$
    – Arno
    Commented Nov 28, 2022 at 12:37
  • $\begingroup$ @Arno Ah, so what you're suggesting is that what François calls a “Dedekind real” in his answer is an element of $\{x\in\mathbb{R} : \forall r\in\mathbb{Q}.(r\leq x\lor x\leq r)\}$ (or some similar such thing) where $\mathbb{R}$ is the set of what are called Dedekind reals in the references I gave in my other comment? $\endgroup$
    – Gro-Tsen
    Commented Nov 28, 2022 at 13:15
  • $\begingroup$ @Gro-Tsen There are indeed several notions of "Dedekind real", all of which are reasonable in their respective contexts. There's an attempt to gather these notions here on the nLab: ncatlab.org/nlab/show/Dedekind+cut As for my answer, I'm thinking of Dedekind cuts where each side is a decidable open convex set (which may both omit a rational filler, if one exists). However, I think "covering cuts", as you described, probably work just as well. $\endgroup$ Commented Nov 29, 2022 at 1:09
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In classical logic, using the ZF axioms, one can show that there is an isomorphism between the Dedekind cuts in the rationals, and the equivalence classes of Cauchy sequences. One can also (without AC) choose a representative from each equivalence class of Cauchy sequences. (EDIT: In high school one might chose decimal fractions, and represent $\pi$ by the sequence $(3, 3.1, 3.14,\ldots)$; a more sophisticated approach might choose continued fractions and represent $\pi$ by the sequence $(3, 22/7, 333/106,\ldots)$.

The fundamental theorem of algebra (every non-constant polynomial with real or complex coefficients has a zero in the complex numbers) can be proved without AC. In fact, there is a quite explicit algorithm that computes, for each irreducible polynomial (with leading coefficient 1, to be on the safe side), the roots of this polynomial continuously from the coefficients.

In constructive mathematics or intuitionistic logic, the story is different, as Francois Dorais explains in his answer.

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    $\begingroup$ I was looking for a reference for this result of Ernst Specker, here it is: MR0256880 ams.org/mathscinet-getitem?mr=256880 Note that the result is peculiar: For each $m \geq 1$ there is a continuous function that returns the $m$-element multiset of the roots of the (not necessarily irreducible) polynomial of degree $m$, but there is no continuous function that picks just one element from that multiset except in the case $m = 1$! $\endgroup$ Commented Jun 21, 2012 at 22:29
  • $\begingroup$ @FrançoisG.Dorais, what is the topology on multisets according to which that function is continuous? $\endgroup$
    – LSpice
    Commented Nov 7, 2022 at 18:31
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    $\begingroup$ @LSpice The quotient of $\mathbb{C}^n$ under permutation of coordinates. $\endgroup$ Commented Nov 7, 2022 at 21:28
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In an intuitionistic setting, the exact choice principles that it requires does indeed depend on the definition of the reals that you start with. If your complex numbers are defined as some sequence of approximations (by the rationals or some other system), the existence of complex roots of arbitrary complex numbers is equivalent to being able to consistently choose a branch of the roots for each approximation.

The axiom of weak countable choice (WCC) which follows both from countable choice and from LEM is often introduced as a sufficient choice principle to prove the fundamental theorem of algebra. It is just the restriction of countable choice to the case where at most one of the sets is not a singleton so that only one choice needs to be made (but where you can't tell for which of the countable number of sets you need to make a choice).

If you have omniscience you can just reduce it to a single choice, so in classical logic this requires no choice principle, and so the FTA holds in ZF (and much weaker systems). On the other hand, weak countable choice, fails for Sh(X) where X is any locally connected Tychonoff space though, and for smooth topoi where it is false that every number that squares to 0 is zero and where nilpotent infinitesimals are important, roots will behave fairly differently from in Set.

So there are plenty of very natural models where key theorems like the FTA may need to be rephrased in some way. One approach in those cases is to avoid choice entirely by rephrasing it in terms of (something that is classically equivalent to) multisets of roots.

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