Great question!
The answer is Yes. Let me elaborate a little. The question is more generally about the left adjoint to the inclusion $\mathrm{An}\to \mathrm{CondAn}$ from anima to condensed anima. This left adjoint is only partially defined; what exists in general is the functor $F: \mathrm{CondAn}\to \mathrm{Pro}(\mathrm{An})$ from condensed anima to pro-anima. Then $F(X)$ is an anima precisely when the left adjoint to $\mathrm{An}\to \mathrm{CondAn}$ exists on $X$, in which case it equals $F(X)$.
Lemma. The functor $F$ inverts the map $X\times [0,1]\to X$ for any condensed anima $X$.
In other words, for any condensed anima $X$ and any anima $Y$, the map
$$ \mathrm{Hom}(X,Y)\to \mathrm{Hom}(X\times [0,1],Y) $$
is an isomorphism. Writing $X$ as a colimit of profinite sets $S$, this reduces to the case $X=S$. But then the condensed anima $\mathrm{Hom}(S,Y)$ is actually itself an anima (if $S=\mathrm{lim}_i S_i$, it is the colimit $\mathrm{colim}_i \mathrm{Hom}(S_i,Y)$), and by adjunction one reduces to the case that $X=\ast$. In this case, this is part of Lemma 11.9 in Analytic Geometry.
The lemma shows that $F$ factors over a functor
$$\mathrm{CondAn}[W^{-1}]\to \mathrm{Pro}(\mathrm{An})$$
from the $\infty$-category obtained from $\mathrm{CondAn}$ by inverting homotopy equivalences.
In particular, any condensed anima $X$ which is homotopy equivalent to an anima $Y$ has the property that $F(X)=Y$. In particular, if $X$ comes from a contractible topological space, then $F(X)=\ast$.
Now if $X$ is just locally contractible, then one can find a cover $X=\bigcup_i U_i$ by contractible $U_i$, and then covers $U_i\cap U_j=\bigcup_k U_{ijk}$, etc., leading to a hypercover of $X$ by disjoint unions of contractible $U\subset X$. As $F$ commutes with colimits, this writes $F(X)$ as a colimit of disjoint unions of points, and hence $F(X)$ is an anima (which is the usual (weak) homotopy type).