3
$\begingroup$

I have a linear system \begin{align*} \left[\begin{array}{cccc} 1 & 2 & 1 & -1 \\ 3 & 2 & 4 & 4 \\ 4 & 4 & 3 & 4 \\ 2 & 0 & 1 & 5 \\ \end{array}\right] \left[\begin{array}{c} w \\ x \\ y \\z \end{array}\right] = \left[\begin{array}{c} 5 \\ 16 \\ 22 \\ 15 \end{array}\right], \end{align*} whose matrix $\bf{A}$ is not diagonally dominant. What are the iterative methods that can be used to find the solution? I have tried Jacobi method, Gauss-Seidel method and SOR method but nothing works (the output diverges). The answer is ${\bf x}=[16,-6,-2,-3]^T$.

$\endgroup$
2
  • 1
    $\begingroup$ Why do you want to use an iterative method on a dense 4x4 matrix in the first place? What is the underlying problem? $\endgroup$ Commented Apr 13, 2022 at 22:06
  • $\begingroup$ @FedericoPoloni I had a large sparse system from Poisson equation and was considering a few alternatives to solve the system. This is my toy problem. What methods would you suggest for this dense system/matrix? $\endgroup$
    – mohd
    Commented Apr 14, 2022 at 0:11

2 Answers 2

1
$\begingroup$

You can see your equation as $f(u)=Au-b$, with $f(u)=0$. You can use some numerical method to solve it. One way is to use the minimization problem $$\min_u g(u),\qquad g(u)=\frac{1}{2}\|f(u)\|^2.$$ This gives you the equation $$0=\nabla g(u)=A^T(Au-b)\quad \text{ or } \quad A^TAu=A^Tb$$ which gives you the possible minimizers.

To your matrix $A$ and vector $b$, you can use the conjugate gradient method to solve $$A^TAu=A^Tb,$$ and it gives you the answer in four steps.

If you prefer to play with more steps, you can try gradient descent method.

You can find more searching for "\(Au=b\) gradient " on SearchOnMath.

Note: If you use the gradient descent method to minimize $h(u)=u^TAu-2u^Tb$ directly, you are going in the direction $$\frac{du}{dt}=- \nabla h(u)=-2(Au-b),$$ which is unstable, since $A$ has one negative eigenvalue and three positive ones.

$\endgroup$
4
  • $\begingroup$ Thank you very much for your answer and the links provided. I learnt about these two methods briefly before, but didn't use them since the matrix was not symmetric. I didn't know we can use CG to non-symmetric matrix. Hence, I just tried a few basic methods such as Jacobi, Gauss-Seidel and SOR. $\endgroup$
    – mohd
    Commented Apr 14, 2022 at 0:33
  • $\begingroup$ That's good if it helps you. I agree that a good method is usually problem-based, as pointed out by @FedericoPoloni. $\endgroup$ Commented Apr 14, 2022 at 18:40
  • $\begingroup$ Here is a particular discussion example "Solve this specific large sparse system of linear equations". $\endgroup$ Commented Apr 14, 2022 at 18:47
  • $\begingroup$ Thanks very much for your suggestions. I really appreciate it! $\endgroup$
    – mohd
    Commented Apr 18, 2022 at 6:43
3
$\begingroup$

I suggest not to use CG on the normal equations as suggested in the other answer, as it converts your system into one with squared condition number $\kappa(A)^2$, which will negatively affect your accuracy.

There is a different Krylov-space-based method that works for nonsymmetric systems, GMRES.

Remarks on convergence:

  • Today Krylov-based methods are typically preferred to classical iterative methods such as Jacobi and Gauss-Seidel, unless one is severely constrained by the hardware architecture.

  • On a $4\times 4$ system GMRES will converge in 4 iterations, and overall it will be slower than any reasonable direct method.

  • Unfortunately there is little you can infer about the convergence for larger matrices from this $4\times 4$ experiment, since the first three iterations are too few to get a glimpse of the convergence curve.

  • As with CG, the real trick of the trade for a large system is preconditioning it, i.e., turning it into a modified system $PAx=Pb$ with better convergence properties. This is a huge research topic, and the best preconditioners are often problem-based.

$\endgroup$
1
  • $\begingroup$ thanks very much for your comments. I will have have a look at GMRES! $\endgroup$
    – mohd
    Commented Apr 18, 2022 at 6:43

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .