1
$\begingroup$

Let $(X,L)$ be a polarized smooth projective variety. Let $D$ be a smooth irreducible divisor in $X$. Let $0<c<1$ be a real number. We denote $cD$ as $\Delta$. We can define the $\alpha$ invariant or the global log canonical threshold of the pair $(X,L,\Delta)$ as:

$$ \alpha(L,\mu_{\Delta}) = \inf_{D_{m}} \mathrm{lct}_{X}(X,D_{m}+\Delta)$$

where $m$ is a positive integer and $D_{m}$ is the zero divisor of some $s_{m}\in H^{0}(X,mL)$. There is also an analytic way to define this invariant as in the last section of Robert J.Berman's paper A thermodynamical formalism for Monge-Ampere equations, Moser-Trudinger inequalities and Kahler-Einstein metrics: https://arxiv.org/abs/1011.3976 .

My question is whether we know that this invariant is always positive as in the case where $\Delta$ is trivial?

$\endgroup$

1 Answer 1

1
$\begingroup$

I think the definition of the $\alpha$ invariant is slightly off. I think you want to consider $\mathrm{lct}_{(X,\Delta)}(\frac{1}{m}D_m)$. The usual way I've seen this written is $$ \alpha(L) = \inf_{D \sim_\mathbb{Q} L} \mathrm{lct}_{(X,\Delta)}(D) $$ where the infimum runs over all divisors $\mathbb{Q}$-linearly equivalent to $L$.

In any case, this is Theorem 9.14 in this paper of Boucksom, Hisamoto and Jonsson. It is also proved under the assumption that $L$ is big rather than ample by Blum-Jonsson, Theorem A.

$\endgroup$
1
  • $\begingroup$ Thanks a lot for bringing this paper to my attention! $\endgroup$
    – Chenxi Yin
    Feb 23, 2022 at 21:19

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.