3
$\begingroup$

Is there a reference discussing the notion of 'free horizontal closure' for an 'almost $2$-category', where all that's missing are some horizontal composites of $2$-cells?

The motivation for this question is a more restrictive situation encountered in the wild, listed below.

Suppose we have a $2$-category $\mathfrak{D}$ together with a collection of objects ${\bf Ob}_\mathfrak{C}\subseteq{\bf Ob}_\mathfrak{D}$, and for each pair of objects $X,Y\in{\bf Ob}_\mathfrak{C}$ we have a category $\mathfrak{C}(X,Y)\subseteq\mathfrak{D}(X,Y)$ such that the $1$-cells of each component category match, but $\mathfrak{C}(X,Y)$ is missing some horizontal composites of $2$-cells from product categories $\mathfrak{C}(Z,Y)\times\mathfrak{C}(X,Z)$ for $Z\in{\bf Ob}_\mathfrak{C}$.

We can consider the smallest sub-$2$-category $\mathfrak{D}_\mathfrak{C}$ of $\mathfrak{D}$ containing all of $\mathfrak{C}$, and this should enjoy a nice universal property for 'almost pseudofunctors' defined out of $\mathfrak{C}$ in the following sense: any 'almost pseudofunctor' $$P:\mathfrak{C}\to\mathfrak{B}$$ sending the objects, $1$-cells and $2$-cells of $\mathfrak{C}$ to objects, $1$-cells and $2$-cells of $\mathfrak{B}$ in a way that respects the data existing in $\mathfrak{C}$ canonically gives rise to a unique pseudofunctor $\hat P:\mathfrak{D}_\mathfrak{C}\to\mathfrak{B}$ such that enter image description here commutes, so 'almost pseudofunctors' out of $\mathfrak{C}$ uniquely determine pseudofunctors out of $\mathfrak{D}_\mathfrak{C}$.

I'm curious if there's anything written up on the more general notion of 'free horizontal completion' for a collection of objects, a category for each pair of objects, and an existing notion of horizontal composition for $1$-cells in each component category. Any references are appreciated.

$\endgroup$
4
  • $\begingroup$ What is your motivating example? $\endgroup$ Commented Feb 20, 2022 at 11:01
  • $\begingroup$ @PaulTaylor A $2$-fibration related to externalization in the sense of Jacobs's book, p.421 -- it's a generalization of the stuff discussed in that section. $\endgroup$
    – Alec Rhea
    Commented Feb 20, 2022 at 11:27
  • $\begingroup$ Even if you don't have all horizontal composites, do you have all whiskerings (i.e. horizontal composites of a 2-cell with the identity 2-cell on some 1-cell)? $\endgroup$ Commented Feb 20, 2022 at 20:18
  • $\begingroup$ @TimCampion I have left whiskerings, not right ones. $\endgroup$
    – Alec Rhea
    Commented Feb 22, 2022 at 0:27

1 Answer 1

3
$\begingroup$

There are probably many ways to think about this. Here is one. I fear it might not be terribly specific to your situation.

You have a $\Theta_2$-set, i.e. a presheaf on Joyal's category $\Theta_2$. There is a nerve functor $\nu_2 : 2Cat \to \widehat{\Theta_2}= Fun(\Theta_2^{op},Set)$ (coming from the fact that $\Theta_2$ is a full subcategory of $2Cat$), but since you're missing horizontal composites, your $\Theta_2$-set is not in the image of $\nu_2$.

However, the image of $\nu_2$ is a reflective subcategory of $\widehat{\Theta}$, and the localization is easy to describe: it consists of those objects $X$ which are right orthogonal to the generalized spine inclusions, which surprisingly I'm having difficulty locating a reference for at the moment. This is a "baby" version of the Theta-space or Theta-set presentations of $(\infty,2)$-categories, and a generalization of the fact that the essential image of the usual nerve functor from 1-categories to simplicial sets is characterized by the unique-inner-horn-filler property (see 3.8 here) [1].

One way to say it is that that we localize $\widehat{\Theta_2}$ at the smallest set of maps $S$ with the following two properties:

  1. Note that each object of $\Theta$ comes with a natural bipointing by its "first" and "last" objects $\bot$ and $\top$. If $\theta,\zeta \in \Theta$, then $$\nu_2(\theta) \vee \nu_2(\zeta) \to \nu_2(\theta \vee \zeta)$$ is in $S$. Here the "wedge sum" $A \vee B$ is the pushout $A \cup_\ast B$ where on $A$ we use the "last" point $\top$ and on $B$ we use the "first" point $\bot$ -- the map above takes the wedge sum in two different categories, and the map is the resulting comparison map, which can be thought of as "filling in the horizontal composites".

  2. If $A \to B$ is in $S \cap \Theta_1$, then $$\Sigma(A) \to \Sigma(B)$$ is in $S$. Here, we observe that the usual suspension functor $\Sigma : 1Cat \to 2Cat$ (which carries $C$ to the 2-category $\Sigma C$ with two objects $\{0,1\}$ with $Hom(0,0) = Hom(1,1) = \ast, Hom(1,0) = \emptyset, Hom(0,1) = C$) carries $\Theta_1$ (which is a full subcategory of $\Theta_2$ and is isomorphic to $\Delta$) to $\Theta_2$. We left Kan extend to obtain a functor which we also call $\Sigma: \widehat{\Theta_1} \to \widehat{\Theta_2}$, and that's what we're applying above. The above map $A \to B$ can be thought of as "filling in the vertical composites".

In order to reflect your $\Theta$-set $X$ into the image of $\nu$, you do what one can always do with such a localization -- wherever you see a map $A \to X$ with $A \to B \in S$, with no extension to $B \to X$, you take a pushout in $\widehat{\Theta_2}$. Whenever you see a map $A \to X$ with two distinct extensions $B \to X$, collapse them together. Do this repeatedly until you can't anymore. This can be seen as a case of the small object argument.

The fact that you already have all vertical composites means that at least initially you only have to worry about maps in $S$ of the form (1) above. But the property of having all vertical composites might be lost as soon as you start doing the iterative gluing described above. So pretty soon you will have to consider maps of the form (2) as well.

[1] Well, the "spine-like" busieness here doesn't directly generalize inner horns -- for that see here. The directly analogous statement for 1-categories is as follows. We have $\Theta_1 = \Delta$. There is a nerve functor $\nu_1 = \Delta[-] : 1Cat \to \widehat{\Theta_1} = sSet$, which is fully faithful, and whose essential image is characterized as the right orthogonal complement of the following set of morphisms:

$$ \{\Delta[m] \vee \Delta[n] \to \Delta[m+n-1] \mid [m],[n] \in \Delta\}$$

Here $\Delta[m] \vee \Delta[n]$ is obtained from $\Delta[m]$ and $\Delta[n]$ by gluing the last vertex of $\Delta[m]$ to the first vertex of $\Delta[n]$. The map $\Delta[m] \vee \Delta[n] \to \Delta[m+n-1]$ is the one which on vertices sends $i \in [m] \mapsto i$ and $j \in [n] \mapsto m + j$. Note that as categories, $[m+n-1]$ is the pushout of $[m]$ and $[n]$ over a point in this way. The above map of simplicial sets is "filling in the missing composites".

$\endgroup$
1
  • $\begingroup$ This is interesting and tangentially related even if it isn't exactly what I was after, thank you. $\endgroup$
    – Alec Rhea
    Commented Feb 22, 2022 at 0:29

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .