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Let $j: X \to Y$ be a closed embedding. Let $I_{X/Y}$ be the ideal sheaf of this closed embedding. Then there is a exact sequence

$$ I_{X/Y} \to \mathcal{O}_Y \to j_{*}\mathcal{O}_X \to 0$$

One use this exact sequence for computation of $H^i(Y, I_{X/Y})$.

In general it is easy to compute $H^i(Y, \mathcal{O}_Y)$ and $H^i(Y, j_{*}\mathcal{O}_X)$. But how does one determine the maps between $H^i(Y, \mathcal{O}_Y)$ and $H^i(Y, j_{*}\mathcal{O}_X)$? Are there any references where one can find examples of this kind of computation?

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    $\begingroup$ Are you aware that $H^i(Y,j_*\mathcal{O}_X)$ is nothing but $H^i(X,\mathcal{O}_X)$?? $\endgroup$
    – abx
    Commented Nov 1, 2018 at 5:00
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    $\begingroup$ Yes, I'm aware of that. $\endgroup$
    – john
    Commented Nov 1, 2018 at 13:43
  • $\begingroup$ If $Y$ and $X$ are smooth and projective, you can use Hodge theory to identify your morphism to the (conjugate of) the restriction $H^0(Y,\Omega ^i_Y)\rightarrow H^0(X,\Omega ^i_X)$, which may be easier to analyze. $\endgroup$
    – abx
    Commented Nov 1, 2018 at 19:49
  • $\begingroup$ The precise description of the maximal rank conjecture for curves sheds light on why this may be hard, even though the context is a little different (see arxiv.org/pdf/1711.04906.pdf for a statement of the conjecture). $\endgroup$
    – user130124
    Commented Nov 1, 2018 at 19:59

1 Answer 1

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The computation of the restriction morphism $H^i(Y,O_Y) \to H^i(X,O_X)$ is usually non-trivial (unless you know for instance an explicit locally free resolution of the ideal sheaf of $X$ in $Y$).

On $H^0$ this is quite easy, of course.

For $H^1$ one can act as follows: each class in $H^1(Y,O_Y)$ can be represented as an extension $$ 0 \to O_Y \to E \to O_Y \to 0; $$ restricting it to $X$ one obtains an exact sequence $$ 0 \to O_X \to E\vert_X \to O_X \to 0; $$ the restriction map takes the class of the first to the class of the second.

On higher $H^i$ one can use Yoneda representations too, but it becomes more complicated.

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