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This question is a follow-up to this one; see that question for the definition of Banach-Mazur games. There James Hanson showed that ZF+DC proves that there is an undetermined Banach-Mazur game; however, the situation with ZF+$\neg$DC is still open (there was an error in a claimed answer, and this question has been modified from its original form to accommodate that).

I'd like to ask what the ZF-situation is. However, in ZF alone things are rather weird so there are multiple plausible "right" versions of this question. Unfortunately this does make the question rather subjective (presumably based on the answers we somehow pin down which version was "right," but how?), but I think it's within $\epsilon$ of precise for a sufficiently small $\epsilon$.


The most obvious question to ask is whether the result, phrased exactly as previously, continues to hold:

Version 1: Does ZF prove "There is an undetermined Banach-Mazur game"?

On second thought, however, it's not obvious to me that this is the right question. Without DC determinacy is a bit weird, and it's arguably better to talk about quasistrategies. A quasistrategy lays out a nonempty set of "permitted moves" at each stage, with a quasistrategy s being winning for a player if there is no play consistent with s in which that player loses and a game being quasidetermined if it has a winning quasistrategy.

A game is quasidetermined if one player or the other has a winning quasistrategy. In ZF+DC determinacy is the same as quasideterminacy, but in ZF they are distinct. So we can separately ask:

Version 2: Does ZF prove "There is an un-quasidetermined Banach-Mazur game?"

Yet on third thought, even that isn't obviously the right question: it's consistent with ZF that both players have winning quasistrategies in a given game! (Consider "Alternate choosing new elements of an amorphous set.") So we might want to land somewhere in the middle - say that a game is weakly determined if exactly one player has a winning quasistrategy.

Version 3: Is the statement "Every Banach-Mazur game is weakly determined" consistent with ZF?

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  • $\begingroup$ My guess is that looking at Gitik's model would be a good starting point. $\endgroup$
    – Asaf Karagila
    Commented Feb 7, 2020 at 22:26
  • $\begingroup$ @AsafKaragila Yeah, I'm looking at it but it's really complicated. $\endgroup$ Commented Feb 7, 2020 at 22:57
  • $\begingroup$ If it was easy you'd have solved it by now... $\endgroup$
    – Asaf Karagila
    Commented Feb 7, 2020 at 22:57
  • $\begingroup$ @AsafKaragila I meant the Gitik model. $\endgroup$ Commented Feb 7, 2020 at 22:58
  • $\begingroup$ I meant the Gitik model as well. $\endgroup$
    – Asaf Karagila
    Commented Feb 7, 2020 at 22:58

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