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Let $\theta$ and $\tau$ be involutions of a semisimple complex lie algebra $\mathfrak{g}$, and suppose that they have the same Satake diagram. I want to understand why they must be conjugate to one another.

Let $\mathfrak{t}_-$ be a maximal torus in the $(-1)$-eigenspace of $\theta$, and let $\mathfrak{h}$ be a Cartan subalgebra containing $\mathfrak{t}_1$. Then I see that we can conjugate $\tau$ by an automorphism $\sigma$ so that $\sigma^{-1}\tau\sigma|_{\mathfrak{h}}=\theta|_{\mathfrak{h}}$. It will then follow that $(\sigma^{-1}\tau\sigma)\circ\theta$ fixes $\mathfrak{h}$ and further fixes the centralizer of $\mathfrak{t}_1$ (since both $\theta$ and $\sigma^{-1}\tau\sigma$ fix it individually). But this doesn't imply it's the identity map, of course, or even that it's conjugate to the identity (since there are many automorphisms that fix a Cartan pointwise without being conjugate to the identity).

So I'm stuck there. Any help/ideas?

Edit: For clarification, by involution of $\mathfrak{g}$ I mean an automorphism of $\mathfrak{g}$ as a complex lie algebra which is not the identity but composes with itself to the identity.

Satake Diagram: if $\theta$ is an involution of $\mathfrak{g}$, then we can write $\mathfrak{g}=\mathfrak{k}+\mathfrak{p}$, where $\mathfrak{k}$ is the (+1)-eigenspace of $\theta$ and $\mathfrak{p}$ is the $(-1)$-eigenspace of $\theta$. Choosing a maximal torus $\mathfrak{t}_1\subseteq\mathfrak{p}$ (i.e. a maximal abelian subspace consisting of semisimple elements inside $\mathfrak{p}$), we can extend this to a Cartan subalgebra $\mathfrak{h}$ of $\mathfrak{g}$, and choose a Borel by taking a regular element $\gamma\in\mathfrak{t}_1^*$ and perturbing it slightly to a regular element in $\mathfrak{h}^*$. For such a choice of Cartan subalgebra and Borel, we take the corresponding Dynkin diagram from simple positive roots $\{\alpha_1,\dots,\alpha_n\}$ and do the following: if $\alpha_i|_{\mathfrak{t}_1}=0$, color the node for $\alpha_i$ black. If $\alpha_i|_{\mathfrak{t}_1}\neq0$ color the node for $\alpha_i$ white. If $\alpha_j|_{\mathfrak{t}_1}=\alpha_k|_{\mathfrak{t}_1}\neq 0$, then connect the nodes for $\alpha_i$ and $\alpha_j$ by arrows. The resulting diagram is called the 'Satake diagram' of $\theta$, and is well-defined.

Reference: 'Homogeneous Spaces and Equivariant Embeddings' by D.A. Timashev.

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    $\begingroup$ Could you explain or give a reference for what you mean by an involution of the complex algebra, and its Satake diagram? $\endgroup$ Commented Jul 15, 2017 at 6:00
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    $\begingroup$ It seems to me that, if $\sigma$ is the complex conjugation, the elements fixed by $\theta \circ \sigma$ resp. $\tau \circ \sigma$ are real forms of $\mathfrak{g}$ which are uniquely determined up to isomorphism by the resp. Satake diagram. Since these are the same, there is a real isomorphism between them, and I guess this lifts to the one your are looking for, which conjugates $\theta$ and $\tau$. I'll think through it more later. $\endgroup$ Commented Jul 15, 2017 at 18:59
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    $\begingroup$ Note that conjugacy classes of involutions of complex simple Lie algebras are classified by Kac diagrams. See Table 7 in the book: Onishchik and Vinberg, Lie Groups and Algebraic Groups, Springer 1990. For the corresponding theory see Onishchik and Vinberg (Eds.), Lie Groups and Lie Algebras III, EMS vol. 41, Springer 1994. $\endgroup$ Commented Jul 15, 2017 at 20:59
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    $\begingroup$ Concerning relations between $\Bbb C$-linear and $\Bbb C$-antilinear involutions, see this preprint $\endgroup$ Commented Jul 15, 2017 at 21:02
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    $\begingroup$ Table 9 of Onishchik and Vinberg 1990 lists Satake diagrams of real forms of simple complex Lie algebras. On page 274 of this book it is written: This table quite easily implies Theorem 3. Two semisimple Lie algebras over $\Bbb R$ are isomorphic if and only it so are (in the natural sense) their Satake diagrams. $\endgroup$ Commented Jul 15, 2017 at 21:27

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