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In Proposition 1.1 of [Math. Proc. Cambridge Phil. Soc. 64 (1968), No. 2, 251-264], P.M. Cohn famously claimed (without proof) that a commutative domain is atomic if and only if it satisfies the ascending chain condition on principal ideals (ACCP). Some years later, A. Grams [Math. Proc. Cambridge Phil. Soc. 75 (1974), No. 3, 321-329] showed (by way of a counterexample) that Cohn's statement is wrong: Every commutative domain satisfying the ACCP is atomic, but not the other way around.

Grams' construction is commonly acknowledged as the first counterexample to Cohn's claim; and until now (2022-08-14, 13:40 CET), I too have believed that this was indeed the case. However, it appears that Cohn himself had already realized his mistake and sketched a (somewhat easier) counterexample on p. 4, ll. 14-18 of [Amer. Math. Monthly 80 (Jan., 1973), No. 1, 1-18].

In any case, it is natural to wonder if Cohn's claim can be, in a way, fixed by providing a sensible characterization (say, of a somewhat ideal-theoretic flavour) of when a commutative domain (or, more generally, a cancellative commutative monoid) is atomic.

Q. I was confirmed that the question is open and well known (at least in some circles), but haven't found any solid evidence in support of this. Do you happen to know of any papers, conference proceedings, etc. (the older, the better) where the question, although somewhat vague in its formulation, is explicitly stated?

Let me recall that a (multiplicatively written) monoid $H$ is atomic if every non-unit factors as a product of atoms (i.e., non-units that cannot be written as a product of two non-units); and it satisfies the ACCP if there does not exist any (infinite) sequence $x_1, x_2, \ldots$ in $H$ such that $Hx_i H \subsetneq Hx_{i+1} H$ for all $i \in \mathbb N^+$. Accordingly, a domain is atomic if so is the multiplicative monoid $R^\bullet$ of its non-zero elements; and satisfies the ACCP if so does $R^\bullet$.

Edit 1. In the last lines of p. 3 in A. Geroldinger and F. Halter-Koch's monograph Non-Unique Factorizations. Algebraic, Combinatorial and Analytic Theory, the authors cite Grams' example and add that "Up to now, there is no satisfactory ideal-theoretic characterization of atomic domains." The book dates back to 2006, but the question is likely ten to thirty years older.

Edit 2 (addressing a comment by მამუკა ჯიბლაძე). Apart from Grams' and Cohn's counterexamples (to Cohn's statement), atomic commutative domains that do not satisfy the ACCP are constructed by A. Zaks in [J. Algebra 80 (1982), 223-231] (where the author considers certain quotients of a polynomial ring in infinitely many variables and proves that they are atomic without the ACCP) and by M. Roitman in [J. Pure Appl. Algebra 87 (1993), 187-199] (where, in Example 5.1, the author famously shows the existence of an atomic commutative domain $R$ such that the univariate polynomial ring $R[X]$ is not atomic, incidentally producing an atomic commutative domain without the ACCP). More recently, further examples were provided by J. G. Boynton and J. Coykendall [J. Pure Appl. Algebra 223 (2019), 619-625] (where the authors use pullbacks of commutative rings to construct large families of atomic commutative domains without the ACCP) and F. Gotti and B. Li [https://arxiv.org/abs/2111.00170] (where, among other things, the authors construct what appears to be the first-ever example of an atomic commutative monoid ring that does not satisfy the ACCP).

It is definitely much easier to construct cancellative commutative monoids without the ACCP. For instance, S.T. Chapman et al. prove in Corollary 4.4 of [Amer. Math. Monthly 128 (2021), No. 4, 302-321] that, if $r$ is a non-zero rational number smaller than $1$ whose numerator is not $1$, then the additive monoid of the cyclic Puiseux semiring generated by $r$ (i.e., the submonoid of the additive group of the rational field generated by $1, r, r^2, \ldots$) is atomic but does not satisfy the ACCP.

Edit 3. Let me share the following excerpt from an exchange with Alberto Facchini (I'm doing so with his permission): It doesn't really answer my question, but seems worth mentioning.

Let $R$ be a commutative domain. As remarked by Cohn himself, all the notions above are described by the partially ordered set $L_p(R)$ of all principal ideals of $R$. For instance, $R$ satisfies the ACCP if and only if $L_p(R)$ is a noetherian poset, and $R$ satisfies the DCCP if and only if $L_p(R)$ is artinian. It is easily seen that $R$ is atomic if and only if, for every $I \in L_p(R)$, the interval $$ [I,R] :=\{\, J\in L_p(R) \colon I \subseteq J\subseteq R\,\} $$ has a maximal finite chain. Here, a maximal finite chain of the interval $[I,R]$ is a finite chain $I = I_0 \subsetneq I_1 \subsetneq \cdots \subsetneq I_n = R$ of $[I,R]$ that cannot be properly refined into any other finite chain of $[I,R]$. See [A. Facchini and M. Fassina, Factorization of elements in noncommutative rings, II, Comm. Algebra 46 (2018), No. 7, 2928-2946]." I don't know though if that counts as a satisfactory ideal-theoretic characterization."

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    $\begingroup$ @მამუკაჯიბლაძე Yes, every cancellative f.g. commutative monoid is atomic. More generally, if a monoid $H$ is left (or right) duo and locally f.g. up to units (i.e., for each $x \in H$ the smallest divisor-closed submonoid of $H$ containing $x$ is generated by $H^\times A_x H^\times$ for some finite $A_x \subseteq H$, where $H^\times$ is the group of units), then it satisfies the ACC on principal two-sided ideals and hence is factorable, which, considering that left duo monoids are Dedekind-finite, means that every non-unit factors as a product of irreducibles (i.e., $\mid_H$-minimal [...] $\endgroup$ Commented Aug 12, 2022 at 15:30
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    $\begingroup$ [...] non-units, where $\mid_H$ is the divisibility preorder on $H$ (namely, the binary relation on $H$ defined by $x \mid_H y$ iff $y \in HxH$)). A cancellative commutative monoid is, on the other hand, acyclic (i.e., $x \ne uxv$ unless $u$ and $v$ are units) and duo; and in an acyclic monoid, every irred is an atom and vice versa. (In fact, the result on left duo l.f.g.u. monoids I've just mentioned is a rather special case of a much more general thm.) But why this question on cancellative f.g. commutative monoids? Maybe you want to have a look at mathoverflow.net/a/414728/16537 $\endgroup$ Commented Aug 12, 2022 at 15:46
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    $\begingroup$ @მამუკაჯიბლაძე Yes, if an acyclic comm monoid doesn't satisfy the ACCP, then the quotient obtained by modding out the units can't be f.g.: This is a consequence of the results mentioned in my previous comments (note that a cancellative comm monoid is acyclic). As for examples of atomic cancellative comm monoids without the ACCP, see Edit 2 in the OP. And for your last question, are you asking whether every submonoid of $(\mathbb Z^n,+)$ has the ACCP (with $n\in\mathbb N$)? I'm not sure to understand the terminology: You start with a convex cone of $\mathbb R^n$, and then...? $\endgroup$ Commented Aug 13, 2022 at 4:13
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    $\begingroup$ Maybe I got it. We start with finitely many vectors $v_1, \ldots, v_k$ of $\mathbb R^n$ and look at the submonoids of $\{a_1 v_1 + \cdots + a_k v_k \colon a_1, \ldots, a_n \in \mathbb N\}$ under addition, right? I'll think about it, I don't know the answer off the top of my head. $\endgroup$ Commented Aug 13, 2022 at 7:16
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    $\begingroup$ I was rather thinking about monoids of all vectors $v$ with integer coordinates such that $\varphi_k(v)\geqslant0$ for a finite family $\varphi_k$ of linear forms on $\mathbb R^n$. $\endgroup$ Commented Aug 13, 2022 at 13:25

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