Is there a nonprincipal ultrafilter $\omega$ on $\mathbb N$ such that for any metric space $M$ there is an isometry $$(M^\omega)^\omega\to M^\omega?$$ (In other words, the $\omega$-power of $\omega$-power of $M$ is isometric to the $\omega$-power of $M$.)
Comments.
You may assume that $M$ has finite diameter, otherwise $M^\omega$ is an $\infty$-metric space; that is, distance between points might take infinite value.
I want to thank Will Brian for pointing to this post of Andreas Blass. It solves my problem negatively, at least if one assumes some natural condition on the isometry.