Skip to main content
Fix mathjax, and while at it, highlight the quotes.
Source Link
Francois Ziegler
  • 31.5k
  • 6
  • 121
  • 176

I believe the answer to the question in the title is probably Cauchy, who in Méthode simple et générale pour la détermination numérique des coefficients que renferme le développement de la fonction perturbatrice, C. R. Acad. Sci. Paris 11 (1840), 453-475, writes (page 469):

La formule $$ Q = \sum Q_{h,h'} e^{h(p-\varpi)\sqrt{-1}} e^{h'(p'-\varpi')\sqrt{-1}} $$ entraîne l'équation $$ Q_{h,h'} = \frac1{4\pi^2} \int_0^{2\pi} \int_0^{2\pi} Q e^{-h(p-\varpi)\sqrt{-1}} e^{-h'(p'-\varpi')\sqrt{-1}} dp\,dp'. $$

"La formule $$ Q = \sum Q_{h,h'} e^{h(p-\varpi)\sqrt{-1}} e^{h'(p'-\varpi')\sqrt{-1}} $$ entraîne l'équation $$ Q_{h,h'} = \frac1{4\pi^2} \int_0^{2\pi} \int_0^{2\pi} Q e^{-h(p-\varpi)\sqrt{-1}} e^{-h'(p'-\varpi')\sqrt{-1}} dp\\,dp'." $$ SpecializingSpecializing to $\varpi=\varpi'=0$ one gets the requested complex Fourier series and formula for its coefficients.

[Edit: H. Burkhardt in Trigonometrische Reihen und Integrale, Encykl. Math. Wiss. II A 12, p. 929 confirms the above as the first of several papers where Cauchy uses the complex form. Moreover he goes back even further to Laplace who writes in Théorie analytique des probabilités (Paris, 1812), pp. 83-84:

"Take the equation $u=\sum_{x=0}^\infty y_xt^x$. Substitute on both sides $e^{x\varpi\sqrt{-1}}$ for $t^x$... and write $U$ for what $u$ then becomes. Multiplying the equation by $e^{-x\varpi\sqrt{-1}}$ and integrating... the right-hand side boils down to $2\pi y_x$; one has therefore $y_x = \frac1{2\pi}\int U\ d\varpi\ (\cos x\varpi - \sqrt{-1}\sin x\varpi)$".]

Take the equation $u=\sum_{x=0}^\infty y_xt^x$. Substitute on both sides $e^{x\varpi\sqrt{-1}}$ for $t^x$... and write $U$ for what $u$ then becomes. Multiplying the equation by $e^{-x\varpi\sqrt{-1}}$ and integrating... the right-hand side boils down to $2\pi y_x$; one has therefore $y_x = \frac1{2\pi}\int U\ d\varpi\ (\cos x\varpi - \sqrt{-1}\sin x\varpi)$.

Note also that specific complex Fourier series were written much earlier. For instance Lagrange in 1766 computes $$ (1-\alpha e^{i\theta})^{-s} = \sum_{m=0}^{\infty}\binom{-s}{m}(-\alpha)^me^{im\theta} $$ ... except that he still writes everywhere $e^{im\theta}$ in the form $\cos m\theta +\sin m\theta\sqrt{-1}$.

I believe the answer to the question in the title is probably Cauchy, who in Méthode simple et générale pour la détermination numérique des coefficients que renferme le développement de la fonction perturbatrice, C. R. Acad. Sci. Paris 11 (1840), 453-475, writes (page 469):

"La formule $$ Q = \sum Q_{h,h'} e^{h(p-\varpi)\sqrt{-1}} e^{h'(p'-\varpi')\sqrt{-1}} $$ entraîne l'équation $$ Q_{h,h'} = \frac1{4\pi^2} \int_0^{2\pi} \int_0^{2\pi} Q e^{-h(p-\varpi)\sqrt{-1}} e^{-h'(p'-\varpi')\sqrt{-1}} dp\\,dp'." $$ Specializing to $\varpi=\varpi'=0$ one gets the requested complex Fourier series and formula for its coefficients.

[Edit: H. Burkhardt in Trigonometrische Reihen und Integrale, Encykl. Math. Wiss. II A 12, p. 929 confirms the above as the first of several papers where Cauchy uses the complex form. Moreover he goes back even further to Laplace who writes in Théorie analytique des probabilités (Paris, 1812), pp. 83-84:

"Take the equation $u=\sum_{x=0}^\infty y_xt^x$. Substitute on both sides $e^{x\varpi\sqrt{-1}}$ for $t^x$... and write $U$ for what $u$ then becomes. Multiplying the equation by $e^{-x\varpi\sqrt{-1}}$ and integrating... the right-hand side boils down to $2\pi y_x$; one has therefore $y_x = \frac1{2\pi}\int U\ d\varpi\ (\cos x\varpi - \sqrt{-1}\sin x\varpi)$".]

Note also that specific complex Fourier series were written much earlier. For instance Lagrange in 1766 computes $$ (1-\alpha e^{i\theta})^{-s} = \sum_{m=0}^{\infty}\binom{-s}{m}(-\alpha)^me^{im\theta} $$ ... except that he still writes everywhere $e^{im\theta}$ in the form $\cos m\theta +\sin m\theta\sqrt{-1}$.

I believe the answer to the question in the title is probably Cauchy, who in Méthode simple et générale pour la détermination numérique des coefficients que renferme le développement de la fonction perturbatrice, C. R. Acad. Sci. Paris 11 (1840) 453-475, writes (page 469):

La formule $$ Q = \sum Q_{h,h'} e^{h(p-\varpi)\sqrt{-1}} e^{h'(p'-\varpi')\sqrt{-1}} $$ entraîne l'équation $$ Q_{h,h'} = \frac1{4\pi^2} \int_0^{2\pi} \int_0^{2\pi} Q e^{-h(p-\varpi)\sqrt{-1}} e^{-h'(p'-\varpi')\sqrt{-1}} dp\,dp'. $$

Specializing to $\varpi=\varpi'=0$ one gets the requested complex Fourier series and formula for its coefficients.

Edit: H. Burkhardt in Trigonometrische Reihen und Integrale, Encykl. Math. Wiss. II A 12, p. 929 confirms the above as the first of several papers where Cauchy uses the complex form. Moreover he goes back even further to Laplace who writes in Théorie analytique des probabilités (Paris, 1812), pp. 83-84:

Take the equation $u=\sum_{x=0}^\infty y_xt^x$. Substitute on both sides $e^{x\varpi\sqrt{-1}}$ for $t^x$... and write $U$ for what $u$ then becomes. Multiplying the equation by $e^{-x\varpi\sqrt{-1}}$ and integrating... the right-hand side boils down to $2\pi y_x$; one has therefore $y_x = \frac1{2\pi}\int U\ d\varpi\ (\cos x\varpi - \sqrt{-1}\sin x\varpi)$.

Note also that specific complex Fourier series were written much earlier. For instance Lagrange in 1766 computes $$ (1-\alpha e^{i\theta})^{-s} = \sum_{m=0}^{\infty}\binom{-s}{m}(-\alpha)^me^{im\theta} $$ ... except that he still writes everywhere $e^{im\theta}$ in the form $\cos m\theta +\sin m\theta\sqrt{-1}$.

fixed spelling
Source Link
Francois Ziegler
  • 31.5k
  • 6
  • 121
  • 176

I believe the answer to the question in the title is probably Cauchy, who in Méthode simple et générale pour la détermination numérique des coefficients que renferme le développement de la fonction perturbatrice, C. R. Acad. Sci. Paris 11 (1840), 453-475, writes (page 469):

"La formule $$ Q = \sum Q_{h,h'} e^{h(p-\varpi)\sqrt{-1}} e^{h'(p'-\varpi')\sqrt{-1}} $$ entraîne l'équation $$ Q_{h,h'} = \frac1{4\pi^2} \int_0^{2\pi} \int_0^{2\pi} Q e^{-h(p-\varpi)\sqrt{-1}} e^{-h'(p'-\varpi')\sqrt{-1}} dp\\,dp'." $$ Specializing to $\varpi=0$$\varpi=\varpi'=0$ one gets the requested complex Fourier series and formula for its coefficients.

[Edit: H. Burkhardt in Trigonometrische Reihen und Integrale, Encykl. Math. Wiss. II A 12, p. 929 confirms the above as the first of several papers where Cauchy uses the complex form. Moreover he goes back even further to Laplace who writes in TheorieThéorie analytique des probablilitésprobabilités (Paris, 1812), pp. 83-84:

"Take the equation $u=\sum_{x=0}^\infty y_xt^x$. Substitute on both sides $e^{x\varpi\sqrt{-1}}$ for $t^x$... and write $U$ for what $u$ then becomes. Multiplying the equation by $e^{-x\varpi\sqrt{-1}}$ and integrating... the right-hand side boils down to $2\pi y_x$; one has therefore $y_x = \frac1{2\pi}\int U\ d\varpi\ (\cos x\varpi - \sqrt{-1}\sin x\varpi)$".]

Note also that specific complex Fourier series were written much earlier. For instance Lagrange in 1766 computes $$ (1-\alpha e^{i\theta})^{-s} = \sum_{m=0}^{\infty}\binom{-s}{m}(-\alpha)^me^{im\theta} $$ ... except that he still writes everywhere $e^{im\theta}$ in the form $\cos m\theta +\sin m\theta\sqrt{-1}$.

I believe the answer to the question in the title is probably Cauchy, who in Méthode simple et générale pour la détermination numérique des coefficients que renferme le développement de la fonction perturbatrice, C. R. Acad. Sci. Paris 11 (1840), 453-475, writes (page 469):

"La formule $$ Q = \sum Q_{h,h'} e^{h(p-\varpi)\sqrt{-1}} e^{h'(p'-\varpi')\sqrt{-1}} $$ entraîne l'équation $$ Q_{h,h'} = \frac1{4\pi^2} \int_0^{2\pi} \int_0^{2\pi} Q e^{-h(p-\varpi)\sqrt{-1}} e^{-h'(p'-\varpi')\sqrt{-1}} dp\\,dp'." $$ Specializing to $\varpi=0$ one gets the requested complex Fourier series and formula for its coefficients.

[Edit: H. Burkhardt in Trigonometrische Reihen und Integrale, Encykl. Math. Wiss. II A 12, p. 929 confirms the above as the first of several papers where Cauchy uses the complex form. Moreover he goes back even further to Laplace who writes in Theorie analytique des probablilités (Paris, 1812), pp. 83-84:

"Take the equation $u=\sum_{x=0}^\infty y_xt^x$. Substitute on both sides $e^{x\varpi\sqrt{-1}}$ for $t^x$... and write $U$ for what $u$ then becomes. Multiplying the equation by $e^{-x\varpi\sqrt{-1}}$ and integrating... the right-hand side boils down to $2\pi y_x$; one has therefore $y_x = \frac1{2\pi}\int U\ d\varpi\ (\cos x\varpi - \sqrt{-1}\sin x\varpi)$".]

Note also that specific complex Fourier series were written much earlier. For instance Lagrange in 1766 computes $$ (1-\alpha e^{i\theta})^{-s} = \sum_{m=0}^{\infty}\binom{-s}{m}(-\alpha)^me^{im\theta} $$ ... except that he still writes everywhere $e^{im\theta}$ in the form $\cos m\theta +\sin m\theta\sqrt{-1}$.

I believe the answer to the question in the title is probably Cauchy, who in Méthode simple et générale pour la détermination numérique des coefficients que renferme le développement de la fonction perturbatrice, C. R. Acad. Sci. Paris 11 (1840), 453-475, writes (page 469):

"La formule $$ Q = \sum Q_{h,h'} e^{h(p-\varpi)\sqrt{-1}} e^{h'(p'-\varpi')\sqrt{-1}} $$ entraîne l'équation $$ Q_{h,h'} = \frac1{4\pi^2} \int_0^{2\pi} \int_0^{2\pi} Q e^{-h(p-\varpi)\sqrt{-1}} e^{-h'(p'-\varpi')\sqrt{-1}} dp\\,dp'." $$ Specializing to $\varpi=\varpi'=0$ one gets the requested complex Fourier series and formula for its coefficients.

[Edit: H. Burkhardt in Trigonometrische Reihen und Integrale, Encykl. Math. Wiss. II A 12, p. 929 confirms the above as the first of several papers where Cauchy uses the complex form. Moreover he goes back even further to Laplace who writes in Théorie analytique des probabilités (Paris, 1812), pp. 83-84:

"Take the equation $u=\sum_{x=0}^\infty y_xt^x$. Substitute on both sides $e^{x\varpi\sqrt{-1}}$ for $t^x$... and write $U$ for what $u$ then becomes. Multiplying the equation by $e^{-x\varpi\sqrt{-1}}$ and integrating... the right-hand side boils down to $2\pi y_x$; one has therefore $y_x = \frac1{2\pi}\int U\ d\varpi\ (\cos x\varpi - \sqrt{-1}\sin x\varpi)$".]

Note also that specific complex Fourier series were written much earlier. For instance Lagrange in 1766 computes $$ (1-\alpha e^{i\theta})^{-s} = \sum_{m=0}^{\infty}\binom{-s}{m}(-\alpha)^me^{im\theta} $$ ... except that he still writes everywhere $e^{im\theta}$ in the form $\cos m\theta +\sin m\theta\sqrt{-1}$.

Laplace reference added
Source Link
Francois Ziegler
  • 31.5k
  • 6
  • 121
  • 176

I believe the answer to the question in the title is probably Cauchy, who in Méthode simple et générale pour la détermination numérique des coefficients que renferme le développement de la fonction perturbatrice, C. R. Acad. Sci. Paris 11 (1840), 453-475, writes (page 469):

"La formule $$ Q = \sum Q_{h,h'} e^{h(p-\varpi)\sqrt{-1}} e^{h'(p'-\varpi')\sqrt{-1}} $$ entraîne l'équation $$ Q_{h,h'} = \frac1{4\pi^2} \int_0^{2\pi} \int_0^{2\pi} Q e^{-h(p-\varpi)\sqrt{-1}} e^{-h'(p'-\varpi')\sqrt{-1}} dp\\,dp'." $$ Specializing to $\varpi=0$ one gets the requested complex Fourier series and formula for its coefficients.

Note that[Edit: H. Burkhardt in Trigonometrische Reihen und Integrale, Encykl. Math. Wiss. II A 12, p. 929 confirms the above as the first of several papers where Cauchy does it hereuses the complex form. Moreover he goes back even further to Laplace who writes in two variables -Theorie analytique des probablilités (Paris, 1812), pp. 83-84:

"Take the equation $u=\sum_{x=0}^\infty y_xt^x$. Substitute on both sides $e^{x\varpi\sqrt{-1}}$ for $t^x$... and write $U$ for what $u$ then becomes. Multiplying the equation by $e^{-x\varpi\sqrt{-1}}$ and integrating... the right- maybe someone with easy accesshand side boils down to his collected works can find an earlier occurrence in$2\pi y_x$; one variablehas therefore $y_x = \frac1{2\pi}\int U\ d\varpi\ (\cos x\varpi - \sqrt{-1}\sin x\varpi)$".]

Note also that specific complex Fourier series were written much earlier. For instance Lagrange in 1766 computes $$ (1-\alpha e^{i\theta})^{-s} = \sum_{m=0}^{\infty}\binom{-s}{m}(-\alpha)^me^{im\theta} $$ ... except that he still writes everywhere $e^{im\theta}$ in the form $\cos m\theta +\sin m\theta\sqrt{-1}$.

I believe the answer to the question in the title is probably Cauchy, who in Méthode simple et générale pour la détermination numérique des coefficients que renferme le développement de la fonction perturbatrice, C. R. Acad. Sci. Paris 11 (1840), 453-475, writes (page 469):

"La formule $$ Q = \sum Q_{h,h'} e^{h(p-\varpi)\sqrt{-1}} e^{h'(p'-\varpi')\sqrt{-1}} $$ entraîne l'équation $$ Q_{h,h'} = \frac1{4\pi^2} \int_0^{2\pi} \int_0^{2\pi} Q e^{-h(p-\varpi)\sqrt{-1}} e^{-h'(p'-\varpi')\sqrt{-1}} dp\\,dp'." $$ Specializing to $\varpi=0$ one gets the requested complex Fourier series and formula for its coefficients.

Note that Cauchy does it here in two variables -- maybe someone with easy access to his collected works can find an earlier occurrence in one variable.

Note also that specific complex Fourier series were written much earlier. For instance Lagrange in 1766 computes $$ (1-\alpha e^{i\theta})^{-s} = \sum_{m=0}^{\infty}\binom{-s}{m}(-\alpha)^me^{im\theta} $$ ... except that he still writes everywhere $e^{im\theta}$ in the form $\cos m\theta +\sin m\theta\sqrt{-1}$.

I believe the answer to the question in the title is probably Cauchy, who in Méthode simple et générale pour la détermination numérique des coefficients que renferme le développement de la fonction perturbatrice, C. R. Acad. Sci. Paris 11 (1840), 453-475, writes (page 469):

"La formule $$ Q = \sum Q_{h,h'} e^{h(p-\varpi)\sqrt{-1}} e^{h'(p'-\varpi')\sqrt{-1}} $$ entraîne l'équation $$ Q_{h,h'} = \frac1{4\pi^2} \int_0^{2\pi} \int_0^{2\pi} Q e^{-h(p-\varpi)\sqrt{-1}} e^{-h'(p'-\varpi')\sqrt{-1}} dp\\,dp'." $$ Specializing to $\varpi=0$ one gets the requested complex Fourier series and formula for its coefficients.

[Edit: H. Burkhardt in Trigonometrische Reihen und Integrale, Encykl. Math. Wiss. II A 12, p. 929 confirms the above as the first of several papers where Cauchy uses the complex form. Moreover he goes back even further to Laplace who writes in Theorie analytique des probablilités (Paris, 1812), pp. 83-84:

"Take the equation $u=\sum_{x=0}^\infty y_xt^x$. Substitute on both sides $e^{x\varpi\sqrt{-1}}$ for $t^x$... and write $U$ for what $u$ then becomes. Multiplying the equation by $e^{-x\varpi\sqrt{-1}}$ and integrating... the right-hand side boils down to $2\pi y_x$; one has therefore $y_x = \frac1{2\pi}\int U\ d\varpi\ (\cos x\varpi - \sqrt{-1}\sin x\varpi)$".]

Note also that specific complex Fourier series were written much earlier. For instance Lagrange in 1766 computes $$ (1-\alpha e^{i\theta})^{-s} = \sum_{m=0}^{\infty}\binom{-s}{m}(-\alpha)^me^{im\theta} $$ ... except that he still writes everywhere $e^{im\theta}$ in the form $\cos m\theta +\sin m\theta\sqrt{-1}$.

fixed sign error
Source Link
Francois Ziegler
  • 31.5k
  • 6
  • 121
  • 176
Loading
added 664 characters in body; edited body
Source Link
Francois Ziegler
  • 31.5k
  • 6
  • 121
  • 176
Loading
Source Link
Francois Ziegler
  • 31.5k
  • 6
  • 121
  • 176
Loading