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Joseph O'Rourke
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This may not be what you seek, but in the 1996 paper, "Anisotropic refinement algorithms for finite elements" by Goodman, Samuelsson, and Szepessy (.ps link), they show an example of a function $u(x,y)=\frac{1}{2} y^2$, independent of $x$, which solves $\Delta u = 1$ on $\mathbb{R}^2$. But with the triangulation shown below, with $\delta \ll \epsilon$, as $\delta \rightarrow 0$, the finite element equation approximates $\Delta u = 0$ instead of $\Delta u = 1$.
      Nonconvergence http://cs.smith.edu/%7Eorourke/MathOverflow/Nonconvergence.jpgNonconvergence

This may not be what you seek, but in the 1996 paper, "Anisotropic refinement algorithms for finite elements" by Goodman, Samuelsson, and Szepessy (.ps link), they show an example of a function $u(x,y)=\frac{1}{2} y^2$, independent of $x$, which solves $\Delta u = 1$ on $\mathbb{R}^2$. But with the triangulation shown below, with $\delta \ll \epsilon$, as $\delta \rightarrow 0$, the finite element equation approximates $\Delta u = 0$ instead of $\Delta u = 1$.
      Nonconvergence http://cs.smith.edu/%7Eorourke/MathOverflow/Nonconvergence.jpg

This may not be what you seek, but in the 1996 paper, "Anisotropic refinement algorithms for finite elements" by Goodman, Samuelsson, and Szepessy (.ps link), they show an example of a function $u(x,y)=\frac{1}{2} y^2$, independent of $x$, which solves $\Delta u = 1$ on $\mathbb{R}^2$. But with the triangulation shown below, with $\delta \ll \epsilon$, as $\delta \rightarrow 0$, the finite element equation approximates $\Delta u = 0$ instead of $\Delta u = 1$.
      Nonconvergence

w changed to u to be closer to question.
Source Link
Joseph O'Rourke
  • 150.9k
  • 36
  • 358
  • 958

This may not be what you seek, but in the 1996 paper, "Anisotropic refinement algorithms for finite elements" by Goodman, Samuelsson, and Szepessy (.ps link), they show an example of a function $w(x,y)=\frac{1}{2} y^2$$u(x,y)=\frac{1}{2} y^2$, independent of $x$, which solves $\Delta w = 1$$\Delta u = 1$ on $\mathbb{R}^2$. But with the triangulation shown below, with $\delta \ll \epsilon$, as $\delta \rightarrow 0$, the finite element equation approximates $\Delta w = 0$$\Delta u = 0$ instead of $\Delta w = 1$$\Delta u = 1$.
      Nonconvergence http://cs.smith.edu/%7Eorourke/MathOverflow/Nonconvergence.jpg

This may not be what you seek, but in the 1996 paper, "Anisotropic refinement algorithms for finite elements" by Goodman, Samuelsson, and Szepessy (.ps link), they show an example of a function $w(x,y)=\frac{1}{2} y^2$, independent of $x$, which solves $\Delta w = 1$ on $\mathbb{R}^2$. But with the triangulation shown below, with $\delta \ll \epsilon$, as $\delta \rightarrow 0$, the finite element equation approximates $\Delta w = 0$ instead of $\Delta w = 1$.
      Nonconvergence http://cs.smith.edu/%7Eorourke/MathOverflow/Nonconvergence.jpg

This may not be what you seek, but in the 1996 paper, "Anisotropic refinement algorithms for finite elements" by Goodman, Samuelsson, and Szepessy (.ps link), they show an example of a function $u(x,y)=\frac{1}{2} y^2$, independent of $x$, which solves $\Delta u = 1$ on $\mathbb{R}^2$. But with the triangulation shown below, with $\delta \ll \epsilon$, as $\delta \rightarrow 0$, the finite element equation approximates $\Delta u = 0$ instead of $\Delta u = 1$.
      Nonconvergence http://cs.smith.edu/%7Eorourke/MathOverflow/Nonconvergence.jpg

added 28 characters in body; edited body
Source Link
Joseph O'Rourke
  • 150.9k
  • 36
  • 358
  • 958

This may not be what you seek, but in the 1996 paper, "Anisotropic refinement algorithms for finite elements" by Goodman, Samuelsson, and Szepessy (.ps link), they show an example of a function $w(x,y)=\frac{1}{2} y^2$, independent of $x$, which solves $\Delta w = 1$ on $\mathbb{R}^2$. But with the triangulation shown below, with $\delta \ll \epsilon$, as $\delta \rightarrow 0$, the finite element equation approximates $\Delta w = 0$ instead of $\Delta w = 1$.
      Nonconvergence http://cs.smith.edu/%7Eorourke/MathOverflow/Nonconvergence.jpg

This may not be what you seek, but in the 1996 paper, "Anisotropic refinement algorithms for finite elements" by Goodman, Samuelsson, and Szepessy (.ps link), they show an example of a function $w(x,y)=\frac{1}{2} y^2$, independent of $x$, which solves $\Delta w = 1$ on $\mathbb{R}^2$. But with the triangulation shown below, as $\delta \rightarrow 0$, the finite element equation approximates $\Delta w = 0$ instead of $\Delta w = 1$.
      Nonconvergence http://cs.smith.edu/%7Eorourke/MathOverflow/Nonconvergence.jpg

This may not be what you seek, but in the 1996 paper, "Anisotropic refinement algorithms for finite elements" by Goodman, Samuelsson, and Szepessy (.ps link), they show an example of a function $w(x,y)=\frac{1}{2} y^2$, independent of $x$, which solves $\Delta w = 1$ on $\mathbb{R}^2$. But with the triangulation shown below, with $\delta \ll \epsilon$, as $\delta \rightarrow 0$, the finite element equation approximates $\Delta w = 0$ instead of $\Delta w = 1$.
      Nonconvergence http://cs.smith.edu/%7Eorourke/MathOverflow/Nonconvergence.jpg

Source Link
Joseph O'Rourke
  • 150.9k
  • 36
  • 358
  • 958
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