Skip to main content
added 10 characters in body
Source Link
Antonius
  • 460
  • 2
  • 12

Let $\smash{\widehat{\mathbb Z}}^\times=\prod_p{\mathbb Z}_p^\times$$\left(\widehat{\mathbb Z}\right)^\times=\prod_p{\mathbb Z}_p^\times$ be the unit group of the ring $\widehat{\mathbb{Z}}$, which is the profinite completion of $\mathbb Z$. We give it the product topology. For a given prime $p$ let $$ f_p=(1,p)\in\mathbb{Z}_p^\times\ \times\ \prod_{q\ne p}\mathbb{Z}_q^\times. $$ Is the group generated by all $f_p$ dense in $\smash{\widehat{\mathbb{Z}}}^\times$$\left(\widehat{\mathbb{Z}}\right)^\times$?

Let $\smash{\widehat{\mathbb Z}}^\times=\prod_p{\mathbb Z}_p^\times$ be the unit group of the ring $\widehat{\mathbb{Z}}$, which is the profinite completion of $\mathbb Z$. We give it the product topology. For a given prime $p$ let $$ f_p=(1,p)\in\mathbb{Z}_p^\times\ \times\ \prod_{q\ne p}\mathbb{Z}_q^\times. $$ Is the group generated by all $f_p$ dense in $\smash{\widehat{\mathbb{Z}}}^\times$?

Let $\left(\widehat{\mathbb Z}\right)^\times=\prod_p{\mathbb Z}_p^\times$ be the unit group of the ring $\widehat{\mathbb{Z}}$, which is the profinite completion of $\mathbb Z$. We give it the product topology. For a given prime $p$ let $$ f_p=(1,p)\in\mathbb{Z}_p^\times\ \times\ \prod_{q\ne p}\mathbb{Z}_q^\times. $$ Is the group generated by all $f_p$ dense in $\left(\widehat{\mathbb{Z}}\right)^\times$?

Became Hot Network Question
Removed extra "is"
Source Link
gmvh
  • 3.1k
  • 6
  • 27
  • 45

Let $\smash{\widehat{\mathbb Z}}^\times=\prod_p{\mathbb Z}_p^\times$ be the unit group of the ring $\widehat{\mathbb{Z}}$, which is the profinite completion of $\mathbb Z$. We give it the product topology. For a given prime $p$ let $$ f_p=(1,p)\in\mathbb{Z}_p^\times\ \times\ \prod_{q\ne p}\mathbb{Z}_q^\times. $$ Is the group generated by all $f_p$ is dense in $\smash{\widehat{\mathbb{Z}}}^\times$?

Let $\smash{\widehat{\mathbb Z}}^\times=\prod_p{\mathbb Z}_p^\times$ be the unit group of the ring $\widehat{\mathbb{Z}}$, which is the profinite completion of $\mathbb Z$. We give it the product topology. For a given prime $p$ let $$ f_p=(1,p)\in\mathbb{Z}_p^\times\ \times\ \prod_{q\ne p}\mathbb{Z}_q^\times. $$ Is the group generated by all $f_p$ is dense in $\smash{\widehat{\mathbb{Z}}}^\times$?

Let $\smash{\widehat{\mathbb Z}}^\times=\prod_p{\mathbb Z}_p^\times$ be the unit group of the ring $\widehat{\mathbb{Z}}$, which is the profinite completion of $\mathbb Z$. We give it the product topology. For a given prime $p$ let $$ f_p=(1,p)\in\mathbb{Z}_p^\times\ \times\ \prod_{q\ne p}\mathbb{Z}_q^\times. $$ Is the group generated by all $f_p$ dense in $\smash{\widehat{\mathbb{Z}}}^\times$?

`\smash`
Source Link
LSpice
  • 12.9k
  • 4
  • 45
  • 69

Let $\widehat{\mathbb Z}^\times=\prod_p{\mathbb Z}_p^\times$$\smash{\widehat{\mathbb Z}}^\times=\prod_p{\mathbb Z}_p^\times$ be the unit group of the ring $\widehat{\mathbb{Z}}$, which is the profinite completion of $\mathbb Z$. We give it the product topology. For a given prime $p$ let $$ f_p=(1,p)\in\mathbb{Z}_p^\times\ \times\ \prod_{q\ne p}\mathbb{Z}_q^\times. $$ Is the group generated by all $f_p$ is dense in $\widehat{\mathbb{Z}}^\times$$\smash{\widehat{\mathbb{Z}}}^\times$?

Let $\widehat{\mathbb Z}^\times=\prod_p{\mathbb Z}_p^\times$ be the unit group of the ring $\widehat{\mathbb{Z}}$, which is the profinite completion of $\mathbb Z$. We give it the product topology. For a given prime $p$ let $$ f_p=(1,p)\in\mathbb{Z}_p^\times\ \times\ \prod_{q\ne p}\mathbb{Z}_q^\times. $$ Is the group generated by all $f_p$ is dense in $\widehat{\mathbb{Z}}^\times$?

Let $\smash{\widehat{\mathbb Z}}^\times=\prod_p{\mathbb Z}_p^\times$ be the unit group of the ring $\widehat{\mathbb{Z}}$, which is the profinite completion of $\mathbb Z$. We give it the product topology. For a given prime $p$ let $$ f_p=(1,p)\in\mathbb{Z}_p^\times\ \times\ \prod_{q\ne p}\mathbb{Z}_q^\times. $$ Is the group generated by all $f_p$ is dense in $\smash{\widehat{\mathbb{Z}}}^\times$?

edited tags
Link
YCor
  • 63.9k
  • 5
  • 187
  • 286
Loading
added 44 characters in body
Source Link
Antonius
  • 460
  • 2
  • 12
Loading
added 7 characters in body
Source Link
Antonius
  • 460
  • 2
  • 12
Loading
Source Link
Antonius
  • 460
  • 2
  • 12
Loading