It is well known that given a regular velocity field $b: \mathbb{R} \times \mathbb{R}^n \to \mathbb{R}^n$ (say, continuous in time and uniformly Lipshitz in space), the flux $X$ associated to $b$ is a diffeomorphism for every fixed time $t$, and it is easy to deduce from the relation $\partial_t X (t,x)= b (t, X(t,x))$ and using the Gronwall inequality that
$$ \exp \left( -\int_0 ^t |\nabla b (s,X(s,x)| ds \right) \leq ||\nabla_x X(t,x)||\leq \exp \left( \int_0 ^t |\nabla b (s,X(s,x)| ds \right) ,$$
where I denote by $||\cdot ||$ the operator norm. Now, the question is very simple, yet I found little looking for the answer online, and it is: are there similar estimates for $X^{-1} (t,x)$ ? I mean, about $X(t,x)$ we know precisely who $\partial_t X$ is and we have an upper and lower bound on the operator norm of $\nabla _x X(t,x)$, what can we say about $\nabla _x X^{-1}$ ? I managed to get a lower bound on the norm, practically using simply the fact that $||A^{-1}|| \geq \frac{1}{||A||}$, but I don't see how to get an upper bound. The only one I can think of only works if $||A-I||<1$, which is not the case here.
I would bet that there exists an upper bound, because if I think about it, applying $X^{-1} (t,\cdot)$ to a point $x$ simply means going back in time for a time $t$ along the integral line passing from $x$. If there's a a bound going forward, there should be one going backwards.