I have a question about the following statement from the article The asymptotic behavior of the linear transmission problem in viscoelasticity by Alves et al. They state on page 8 that:

Let $\alpha = \dfrac{\rho_1\lambda^2}{\kappa_1 + i\kappa_2\lambda}$ where $\rho_1, \kappa_1, \kappa_2 > 0$. then $$ \operatorname{Coth}(i\alpha L) \to 1, \ \ \text{ when } \ \ n \to \infty $$ where $L > 0$.

Well, firstly, I think they are changing $\alpha$ to $\alpha_{n}$ and leaving $n$ hidden. And doing some mathematical manipulations, I'm getting to

Let $x_n = \Re(\alpha_n L)$ and $y_n = \Im(\alpha_n L)$. Using some properties, I can get $$ \operatorname{Coth}(i\alpha_n L) = \dfrac{\cos(x_n)\sin(x_n)}{\cosh^2 (y_n) - \cos^2(x_n)} - \dfrac{\tanh(y_n)} {\frac{\cos^2(x_n)}{\cosh^2 (y_n)} - 1} $$

From the equality above can I conclude what I want? Why?

I have a question about the following statement from the article

• Alves, M., Rivera, J.M., Sepúlveda, M., Villagrán, O.V. and Garay, M.Z., The asymptotic behavior of the linear transmission problem in viscoelasticity, Math. Nachr. 287 (2014) pp 483-497, doi:10.1002/mana.201200319, (author pdf)

They state on page 8 that:

Let $\alpha = \dfrac{\rho_1\lambda^2}{\kappa_1 + i\kappa_2\lambda}$ where $\rho_1, \kappa_1, \kappa_2 > 0$. then $$ \operatorname{Coth}(i\alpha L) \to 1, \ \ \text{ when } \ \ n \to \infty $$ where $L > 0$.

Well, firstly, I think they are changing $\alpha$ to $\alpha_{n}$ and leaving $n$ hidden. And doing some mathematical manipulations, I'm getting to

Let $x_n = \Re(\alpha_n L)$ and $y_n = \Im(\alpha_n L)$. Using some properties, I can get $$ \operatorname{Coth}(i\alpha_n L) = \dfrac{\cos(x_n)\sin(x_n)}{\cosh^2 (y_n) - \cos^2(x_n)} - \dfrac{\tanh(y_n)} {\frac{\cos^2(x_n)}{\cosh^2 (y_n)} - 1} $$

From the equality above can I conclude what I want? Why?

I have a question about the following statement from an article here. He states on page 490 that:

https://sci-hub.ru/10.1002/mana.201200319

Let $\alpha = \dfrac{\rho_1\lambda^2}{\kappa_1 + i\kappa_2\lambda}$ where $\rho_1, \kappa_1, \kappa_2 > 0$. then $$ \operatorname{Coth}(i\alpha L) \to 1, \ \ \text{ when } \ \ n \to \infty $$ where $L > 0$.

Well, firstly, I think he's changing $\alpha$ to $\alpha_{n}$ and leaving $n$ hidden. And doing some mathematical manipulations, I'm getting to

Let $x_n = \Re(\alpha_n L)$ and $y_n = \Im(\alpha_n L)$. Using some properties, I can get $$ \operatorname{Coth}(i\alpha_n L) = \dfrac{\cos(x_n)\sin(x_n)}{\cosh^2 (y_n) - \cos^2(x_n)} - \dfrac{\tanh(y_n)} {\frac{\cos^2(x_n)}{\cosh^2 (y_n)} - 1} $$

From the equality above can I conclude what I want? Why?

I have a question about the following statement from the article The asymptotic behavior of the linear transmission problem in viscoelasticity by Alves et al. They state on page 8 that:

Let $\alpha = \dfrac{\rho_1\lambda^2}{\kappa_1 + i\kappa_2\lambda}$ where $\rho_1, \kappa_1, \kappa_2 > 0$. then $$ \operatorname{Coth}(i\alpha L) \to 1, \ \ \text{ when } \ \ n \to \infty $$ where $L > 0$.

Well, firstly, I think they are changing $\alpha$ to $\alpha_{n}$ and leaving $n$ hidden. And doing some mathematical manipulations, I'm getting to

Let $x_n = \Re(\alpha_n L)$ and $y_n = \Im(\alpha_n L)$. Using some properties, I can get $$ \operatorname{Coth}(i\alpha_n L) = \dfrac{\cos(x_n)\sin(x_n)}{\cosh^2 (y_n) - \cos^2(x_n)} - \dfrac{\tanh(y_n)} {\frac{\cos^2(x_n)}{\cosh^2 (y_n)} - 1} $$

From the equality above can I conclude what I want? Why?

I have a question about the following statement from an article here. He states on page 490 that:

https://sci-hub.ru/10.1002/mana.201200319

Let $\alpha = \dfrac{\rho_{1}\lambda^{2}}{\kappa_{1} + i\kappa_{2}\lambda}$ where $\rho_{1}, \kappa_{1}, \kappa_{2} > 0$. then $$ \text{Coth}(i\alpha L) \to 1, \ \ \text{when} \ \ n \to \infty $$ where $L > 0$.

Well, firstly, I think he's changing $\alpha$ to $\alpha_{n}$ and leaving $n$ hidden. And doing some mathematical manipulations, I'm getting to

Let $x_{n} = \Re(\alpha_{n}L)$ and $y_{n} = \Im(\alpha_{n}L)$. Using some properties, I can get $$ \text{Coth}(i\alpha_{n} L) = \dfrac{\cos(x_n)\sin(x_n)}{\cosh^{2}(y_n) - \cos^{2}(x_n)} - \dfrac{\tanh(y_n)} {\frac{\cos^{2}(x_n)}{\cosh^{2}(y_n)} - 1} $$

From the equality above can I conclude what I want? Why?

I have a question about the following statement from an article here. He states on page 490 that:

https://sci-hub.ru/10.1002/mana.201200319

Let $\alpha = \dfrac{\rho_1\lambda^2}{\kappa_1 + i\kappa_2\lambda}$ where $\rho_1, \kappa_1, \kappa_2 > 0$. then $$ \operatorname{Coth}(i\alpha L) \to 1, \ \ \text{ when } \ \ n \to \infty $$ where $L > 0$.

Well, firstly, I think he's changing $\alpha$ to $\alpha_{n}$ and leaving $n$ hidden. And doing some mathematical manipulations, I'm getting to

Let $x_n = \Re(\alpha_n L)$ and $y_n = \Im(\alpha_n L)$. Using some properties, I can get $$ \operatorname{Coth}(i\alpha_n L) = \dfrac{\cos(x_n)\sin(x_n)}{\cosh^2 (y_n) - \cos^2(x_n)} - \dfrac{\tanh(y_n)} {\frac{\cos^2(x_n)}{\cosh^2 (y_n)} - 1} $$

From the equality above can I conclude what I want? Why?