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Let f:[a,b]->R$f:[a,b]\rightarrow R$ be a function that is not C^(n+1)$C^{(n+1)}$ on [a,b]$[a,b]$ but its n$n$-th derivative is a Lipschitz function? How does the Lagrange's interpolating polynomial formula change? How does the error approximation change? How can iI use it in order to find Simpson's and Newton's formulas of quadrature? I have searched a lot but I could not find a proper demonstration in any numerical analysis book. Please help!

Let f:[a,b]->R be a function that is not C^(n+1) on [a,b] but its n-th derivative is a Lipschitz function? How does the Lagrange's interpolating polynomial formula change? How does the error approximation change? How can i use it in order to find Simpson's and Newton's formulas of quadrature? I have searched a lot but I could not find a proper demonstration in any numerical analysis book. Please help!

Let $f:[a,b]\rightarrow R$ be a function that is not $C^{(n+1)}$ on $[a,b]$ but its $n$-th derivative is a Lipschitz function? How does the Lagrange's interpolating polynomial formula change? How does the error approximation change? How can I use it in order to find Simpson's and Newton's formulas of quadrature? I have searched a lot but I could not find a proper demonstration in any numerical analysis book. Please help!

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Lagrange's interpolating polynomial

Let f:[a,b]->R be a function that is not C^(n+1) on [a,b] but its n-th derivative is a Lipschitz function? How does the Lagrange's interpolating polynomial formula change? How does the error approximation change? How can i use it in order to find Simpson's and Newton's formulas of quadrature? I have searched a lot but I could not find a proper demonstration in any numerical analysis book. Please help!