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Left closed in review as "Original close reason(s) were not resolved" by Michael Albanese, Alex M., Alexey Ustinov
Left closed in review as "Original close reason(s) were not resolved" by Alex M., Michael Albanese, Brian Hopkins
Post Closed as "Not suitable for this site" by LSpice, Jochen Wengenroth, Steven Landsburg, Vladimir Dotsenko, M.G.
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R.P.
R.P.
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How to prove that 1$1/ ((y+z) x^4) + 1/ ((z+x) y^4) + 1/ ((x+y) z^4) >3\geq 3/22$ for x$x, y, z>0z>0$ such that xyz=1$xyz=1$?

Spurious parenthesis; TeX
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LSpice
LSpice
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How to prove that 1/ ((y+z) x^4) + 1/ ((z+x) y^4) + 1/ ((x+y) z^4) >3/2 for x, y, z>0 such that xyz=1)?

How to prove that $\cfrac{1}{(y+z) x^4} + \cfrac{1}{(x+z) y^4} + \cfrac{1}{(y+x) z^4}\geq3/2$$\dfrac{1}{(y+z) x^4} + \dfrac{1}{(x+z) y^4} + \dfrac{1}{(y+x) z^4}\geq3/2$ for $x, y, z>0$, such that $xyz=1$?

How to prove that 1/ ((y+z) x^4) + 1/ ((z+x) y^4) + 1/ ((x+y) z^4) >3/2 for x, y, z>0 such that xyz=1)?

How to prove that $\cfrac{1}{(y+z) x^4} + \cfrac{1}{(x+z) y^4} + \cfrac{1}{(y+x) z^4}\geq3/2$ for $x, y, z>0$, such that $xyz=1$?

How to prove that 1/ ((y+z) x^4) + 1/ ((z+x) y^4) + 1/ ((x+y) z^4) >3/2 for x, y, z>0 such that xyz=1?

How to prove that $\dfrac{1}{(y+z) x^4} + \dfrac{1}{(x+z) y^4} + \dfrac{1}{(y+x) z^4}\geq3/2$ for $x, y, z>0$, such that $xyz=1$?

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Jogn
Jogn
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How to prove that 1/ ((y+z) x^4) + 1/ ((z+x) y^4) + 1/ ((x+y) z^4) >3/2 for x, y, z>0 such that xyz=1)?

How to prove that $\cfrac{1}{(y+z) x^4} + \cfrac{1}{(x+z) y^4} + \cfrac{1}{(y+x) z^4}\geq3/2$ for $x, y, z>0$, such that $xyz=1$?