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Let $f_n$ and $g_n$ two generalized functions such that :

  • the product $f_n g_n$ is well defined for all $n\in \mathbb{N}$, which means $WF(f_n)+WF(g_n)$ does not contain an element of the form $(x,0)$.
    ( where $WF(u)$ is the wavefront of generalized function $f$$u$)
  • $f_n$ converges to $f$ and $g_n$ converges to $g$ (Weak* topologie).
  • the product $f g$ is well defined.
    My question is : Can we deduce that $f_n g_n$ converge to $f g$ (weak* topologie) ?

Let $f_n$ and $g_n$ two generalized functions such that :

  • the product $f_n g_n$ is well defined for all $n\in \mathbb{N}$, which means $WF(f_n)+WF(g_n)$ does not contain an element of the form $(x,0)$.
    ( where $WF(u)$ is the wavefront of generalized function $f$)
  • $f_n$ converges to $f$ and $g_n$ converges to $g$ (Weak* topologie).
  • the product $f g$ is well defined.
    My question is : Can we deduce that $f_n g_n$ converge to $f g$ (weak* topologie) ?

Let $f_n$ and $g_n$ two generalized functions such that :

  • the product $f_n g_n$ is well defined for all $n\in \mathbb{N}$, which means $WF(f_n)+WF(g_n)$ does not contain an element of the form $(x,0)$.
    ( where $WF(u)$ is the wavefront of generalized function $u$)
  • $f_n$ converges to $f$ and $g_n$ converges to $g$ (Weak* topologie).
  • the product $f g$ is well defined.
    My question is : Can we deduce that $f_n g_n$ converge to $f g$ (weak* topologie) ?
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product of two generalized functions

Let $f_n$ and $g_n$ two generalized functions such that :

  • the product $f_n g_n$ is well defined for all $n\in \mathbb{N}$, which means $WF(f_n)+WF(g_n)$ does not contain an element of the form $(x,0)$.
    ( where $WF(u)$ is the wavefront of generalized function $f$)
  • $f_n$ converges to $f$ and $g_n$ converges to $g$ (Weak* topologie).
  • the product $f g$ is well defined.
    My question is : Can we deduce that $f_n g_n$ converge to $f g$ (weak* topologie) ?