This seems such a simple question, that I fear I must missed some elementary maths.

I am looking for a way to solve $x+x^a = y$ by reference to an already defined function, $a,x,y > 0$ are real.

Failing that a reasonable approximation for $a$ in $(0,1)$.

Many thanks

This seems such a simple question that I fear I must have missed some elementary maths.

I am looking for a way to solve $x+x^a = y$ by reference to an already defined function, $a,x,y > 0$ are real.

Failing that a reasonable approximation for $a$ in $(0,1)$.

Many thanks!

This seems such a simple question, that I fear I must missed some elementary maths.

I am looking for a way to solve x+x^a = y by reference to an already defined function, a,x,y > 0 are real.

Failing that a reasonable approximation for a in (0,1).

Many thanks

This seems such a simple question, that I fear I must missed some elementary maths.

I am looking for a way to solve $x+x^a = y$ by reference to an already defined function, $a,x,y > 0$ are real.

Failing that a reasonable approximation for $a$ in $(0,1)$.

Many thanks